Feb 19, 2020 · Your working isn't that clear. The potential is the negative of the work done by the field to bring $1C$ from a point of zero reference (usually set at infinity) to the specified position.

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Jul 28, 2020 · The formula V = kQ/R gives the potential at the surface of a spherically symmetrical charge, Q, of radius, R (on the surface of your shell). It is found by integrating the, E, field in from infinity. As you point out, the, E, inside the shell is zero, so the potential does not change as you go in from the surface.

May 8, 2019 · So I have a few questions regarding a Van De Graff Generator. With the Equation: V=kQ/r where V is the Voltage Potential, k is the constant, Q is the charge in coulombs and r is the radius of the sphere. 1.) Do I have to use a sphere? Can I use, say a cylinder that is metal? 2.) How does the Charge concept work?

May 8, 2024 · V=Kq/r for a positive point charge. Assume B is the closest distance of approach for any test charge without experiencing a force due to the positive point charge. Now, if I want to move the point charge further towards point A, wouldn't I be performing negative work, and hence the point would have negative potential?

Aug 15, 2024 · $$ V= \frac{1}{r}$$ $$-\nabla V = \frac{1}{r^2} \hat r$$ Which is the correct field direction for all valid points in space You need to use the correct field and not zhat, employing the spherical gradient

May 3, 2021 · The actual solution of this question is to be solved using Gauss' Law. However, I solved for charge inside (Q) using the formula E=kQ/r^2, putting E=+100 N/C and r=+0.1 m but the value doesn't match. Can someone guide me as to why my approach is wrong? Why can't we use the formula E=kQ/r^2?

So if in the equation PE = qV i put V = kQ/r I will have kQq/r which is the potential energy for any two particles, Also, one small, thing, have you replaced the variables q1 and q2 by q and Q? Because q could also mean quantization of a charged particle? $\endgroup$

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Apr 14, 2019 · When dimensions become very small, we are no longer in the realm of classical physics where potentials have mathematical singularities as in the classical 1/r Coulomb potential.