2017年1月10日 · What is the difference between $\ce {O}$ and $\ce {O2}$. If C is carbon and then why $\ce {O2}$ is oxygen.

2014年7月18日 · Here are the MO schemes of NX2 N X 2 (left) and OX2 O X 2 (right). Why is the σ σ -MO formed by the p p AOs energetically above the π π -MO for NX2 N X 2 but not for OX2 O X 2? Can it be explained this way: In second period elements with more than a half filled p p orbitals, the energy pattern of the MOs is regular. In second period elements with less than or …

2014年7月24日 · The second one is nonsense (we cannot have negative concentrations). If you make the assumption that 0.02 − x ≈ 0.02 0.02 − x ≈ 0.02, then the positive root is x = 6.0 ×10−4 x = 6.0 × 10 − 4, not a big difference given the significant figures. If you knew your initial concentration more precisely, this assumption would be invalid.

2012年8月8日 · How can $\ce {CO2}$ be converted into carbon and oxygen? $$\ce {CO2 -> C + O2}$$ Alternatively: $$\ce {CO2 + ? -> C + O2}$$ I'm aware that plants are capable of transforming $\ce {CO2 + H2O}$...

2017年6月21日 · The equation below represents combustion of methane (CHX4 C H X 4, 16.04 g/mol 16.04 g / m o l). Balance the equation, and calculate the mass of water (18.02 g/mol 18.02 g / m o l) formed when 40.0 g 40.0 g of methane is burned.

2016年6月12日 · Does "Mole of Iodine" or any other element that normally appears as diatomic molecules refer to a mole of single atoms (6.02 ×1023 6.02 × 10 23 iodine atoms) or a mole of the molecules (6.02 ×1023 6.02 × 10 23 molecules of I2 I 2)? EDIT: If there is no specification of moles of atoms or moles of molecules, what do I do?

2018年6月27日 · To calculate the dissolved oxygen in water at saturation pressure at 25 °C, we do: $$ D_\\ce{O2} = K_\\mathrm{H} \\times M \\times p_\\mathrm{g} $$ $$ D_\\ce{O2 ...

This webpage explains how to calculate the total concentration after mixing two solutions of different concentrations.

2018年7月24日 · and said "2 moles of water" decomposed to form "2 moles of molecular hydrogen" and "1 mole of molecular oxygen". It is my understanding that there are only 2 molecules of water, not 2 × 6.02 ×1023 2 × 6.02 × 10 23 molecules of water and so on with the other parts of the equation as well. Could someone please clear up my confusion?

2021年1月9日 · Buffer solutions are typically prepared by dissolving an appropriate salt in water and then adjusting the pH p H to the desired position by addition of the conjugate acid or base. For example, to prepare a 100 mM 100 m M ammonium acetate solution at pH 9, p H 9, you’d first prepare a 100 mM 100 m M ammonium acetate, and then add ammonium hydroxide dropwise …