
Graphing Calculator - Desmos
Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more.
Step-by-Step Calculator - Symbolab
Symbolab is the best step by step calculator for a wide range of math problems, from basic arithmetic to advanced calculus and linear algebra. It shows you the solution, graph, detailed …
Prove this $x^3 + y^3 = (x+y)(x^2 - xy + y^2)$ - Mathematics Stack Exchange
2019年2月12日 · Prove this $x^3 + y^3 = (x+y) (x^2 - xy + y^2)$ My attempt Proof - by using [axiomdistributive] and [axiommulcommutative]: $$\begin {split} & (x+y) (x^2 - xy + y^2)\\ &= …
System of Equations Calculator - Symbolab
To solve a system of equations by substitution, solve one of the equations for one of the variables, and substitute this expression into the other equation. Then, solve the resulting equation for …
如何证明y^2=x^3-2只有一组正整数解? - 知乎
目前问题是求 y^2 + 2 = x^3。 满足条件的实数只有 (5,3),(-5,3);5^2 + 2 = 27 = 3^3。 所以只要证明一边等于0,就能得出结果。 但是这种方法好像不够强。 放弃了。 0.383^2 +2 …
elementary number theory - The Diophantine equation $x^2 + 2 = y^3 ...
2013年8月22日 · How to solve the Diophantine equation x2 + 2 = y3 with x, y> 0 ? (x, y are integers.) x=5,y=3 is one solution that can be found through trial and error. There is a standard …
Graph y= (x-2)^2-3 | Mathway
Select a few x x values, and plug them into the equation to find the corresponding y y values. The x x values should be selected around the vertex. Tap for more steps... Graph the parabola …
y=x^(2/3)图像什么样,有图么 - 百度知道
一般地,y=x^α(α为有理数)的函数,即以底数为 自变量,幂为 因变量,指数为常数的函数称为 幂函数。 例如函数y=x^0 、y=x^1、y=x^2、y=x^-1(注:y=x^-1=1/x、y=x^0时x≠0)等都是 …
Graph y=(x+2)(x-3) | Mathway
Select a few x x values, and plug them into the equation to find the corresponding y y values. The x x values should be selected around the vertex. Tap for more steps... Graph the parabola …
Solve (x^2+y^2-1)3-x^2y^3=0 | Microsoft Math Solver
Intersection Number of B = Y 2 −X 3 +X and F = (X 2 +Y 2)3 −4X 2Y 2 using the fact I (P,F ∩ B)= ordP B(F). The key to the solution is that the curve C=V (B) is indeed smooth at P and that a …
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