x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} …

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

QuickMath allows students to get instant solutions to all kinds of math problems, from algebra and equation solving right through to calculus and matrices.

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{1+\sqrt{13}}{2} for x_{1} and \frac{1-\sqrt{13}}{2} for x_{2}.

Simplify (x-3)(x-2) Step 1. Expand using the FOIL Method. Tap for more steps... Step 1.1. Apply the distributive property. Step 1.2. Apply the distributive property. Step 1.3. Apply the …

Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-2\right)^{3}.

A value c c is said to be a root of a polynomial p(x) p x if p(c)=0 p c = 0. The largest exponent of x x appearing in p(x) p x is called the degree of p p . If p(x) p x has degree n n , then it is well …

2020年6月19日 · $$(1-x)(x + x^2 + \cdots + x^n) = x - x^{n+1} = x(1-x^n)$$ Divide both sides by $1-x$, you get what you want to show.

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 3 for x_{1} and -1 for x_{2}.

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.