2021年12月12日 · d/dx denotes the derivative (of a function) with respect to x. Your explanation doesn't distinguish between the action of taking a derivative, versus the derivative itself. I would say that ##\frac d{dx}## is the operator that when applied to a function, produces the derivative of the function with respect to x.

2012年9月2日 · 1) ∫ d/dx f(x) dx = 0 → ∫ f'(x) dx = 0 → f(x) + C = 0 or 2) ∫ d/dx f(x) dx = 0 → d/dx ∫ f(x) dx = 0 → d/dx (F(x) + C) = 0 → f(x) = 0 where F(x) is the integral of f(x) and f'(x) is the derivative of f(x), both with respect to x. Thanks.

2005年11月8日 · Shouldn't we be showing that <f|xf> = <xf|f> for any L2 integrable function f to show that x is hermitian? I'm not able to convince myself that x=x T is equivalent. It seems like you assumed that x is hermitian and showed that the necessary condition is for x=x T which is only the case for finite dimensional systems. In general we cannot assume ...

2014年9月25日 · You wrote ∫f*(i/x^2 d/dx), but that expression is missing a g on the right (and the integration "dx"). Also, you shouldn't write ∫f*(i/x^2 d/dx)g dx = ∫g(-i/x^2 d/dx)f dx, because we still don't know if this holds. Your task is to find out if it does. Integration by parts is an application of the product rule:

2013年11月11日 · The symbol d 2 y/dx 2 represents the derivative (with respect to x) of the derivative with respect to x, or in other words, the 2nd derivative of y with respect to x. It could be written as $$\frac{d}{dx}(\frac{dy}{dx})$$ As a notational shortcut, the above is often written as d 2 y/dx 2. d/dx is the differentiation operator, indicating that we ...

2008年11月4日 · \frac{d}{dx}\bar{f}(x) = \cdots [/tex] and then "thinking" that [tex]\bar{f}[/tex] and [tex]f[/tex] are somehow the same thing, and that you could cancel them out of the equation, so that you are left only with operators on the both sides.

2008年3月27日 · a) Consider the operator x d/dx(where 1st d/dx acts on the function, then x acts on the resulting function by simply multiplying by x )acting on the set of functions of a real variable x for x>0. What are the eigenvalues and the corresponding eigenfunctions of this …

2013年6月20日 · I understand from the equation: df = {\\frac{\\partial f}{\\partial x}} dx + {\\frac{\\partial f}{\\partial y}} dy that: dx \\neq \\partial x . I understand why df \\neq \\partial f (df is the change in f when the change in all the variables is infinitesimal, and \\partial f …

2011年4月30日 · f'(x) means to take the derivative of y with respect to x. (same with y') d/dx means to take the derivative of whatever's after it with respect to x. For example: d/dx (y), would mean to take the derivative of y with respect to x. dy/dx means to take the derivative of y …

2012年8月1日 · Seeing d/dx by itself was too difficult to conceptualise, I can't grasp the meaning of it. For me it was akin to seeing: (sin( /sin(x) + x)y = sin(y)/sin(x) + xy. So, my questions are: 1. Can you simply pull the input of a differential away from the expression -> dx + x = (d + 1)x 2. How do you conceptualise what the meaning of d/dx is.