log(x) * log(x) - log(x) - 2 = 0 simplify this to get: log^2(x) - log(x) - 2 = 0 let y = log(x) and your equation becomes: y^2 - y - 2 = 0 this is a quadratic equation that can be solved by factoring. …

2014年8月14日 · The derivative is f'(x)=(1-logx)/x^2. This is an example of the the Quotient Rule: Quotient Rule . The quotient rule states that the derivative of a function f(x)=(u(x))/(v(x)) is: …

2017年6月15日 · Assuming you mean #xlog_(10)x#... the derivative of #lnx# is #1/x#, so using the change of base law:. #d/(dx)[log x] = d/(dx)[(logx)/(log 10)] = d/(dx)[(lnx)/(ln10)]#

2015年11月20日 · x=1000 Note that when log is not paired with a base, there base is implied to be 10. So, logx can be written as log_10x. log_10x=3 10^(log_10x)=10^3 x=1000

2017年8月14日 · See below. First a couple of remarks: I will asume that log x is log_e x Clearly the expression does not have a single 'value' for x in (0,oo) I will analyse the function f(x) = …

2017年2月9日 · What is the derivative of #f(x)=(log_6(x))^2# ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question

You can put this solution on YOUR website! x^logx = 100x-----Take the log of both sides to get: (logx)(logx) = log100 + logx

2016年6月5日 · It is =-1/(xlog(x)^2). With the chain rule. 1/log(x)=log(x)^-1 So you apply the chain rule to the power and then to the log: d/dxlog(x)^-1=-1*log(x)^-2*d/dxlog(x) =-1 ...

2016年6月16日 · #log y* log x = logx* log y# Answer link. Related questions. What is the common logarithm of 10?

2015年9月11日 · How do you solve #log(x^3)=(logx)^3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models. 1 Answer