rotate_x(mtcars, 'mpg', row.names(mtcars), 45) You can change the rotation angle of the labels as needed ...

Adding the labels option to the scale_x_discrete layer of the plot allows you to change the axis labels. Adding labels to both scale_fill_manual and scale_color_manual allows you to change the legend labels.

2021年10月24日 · library(dplyr) df_list <- list(df1, df2, df3) df <- Reduce(function(x, y) merge(x, y, all=TRUE), df_list) This was a solution to another problem I had, I wanted to simplify merging multiple dataframes. But if you use two dataframes in the list, it works all the same and merging does not rename the columns.

[Note: edited to modernize ggplot syntax] Your example is not reproducible since there is no ex1221new (there is an ex1221 in Sleuth2, so I guess that is what you meant).

2014年1月10日 · You should always get and set these attributes with their accessor functions: use names(x), class(x) and dim(x), not attr(x, "names"), attr(x, "class"), and attr(x, "dim"). What is the justification for that? Is there an example of an unexpected behaviour? Or is this simply a recommendation? On a trivial level I don't see any difference:

In my case several steps of writing and reading data produced one or more columns named "X", X.1",... containing content in the X-column and row numbers in the X.1,...-columns. In my case the content of the X-column should be used as row names and the other X.1,...-columns should be …

Alternatively, it also provides guide_axis(n.dodge = 2) (as guide argument to scale_.. or as x argument to guides) to overcome the over-plotting problem by dodging the labels vertically.

2016年11月1日 · If we apply make.names. make.names(names(z)) #[1] "ID" "x" "y" "V1" "X198101" "X198102" #[7] "X198103" "X198104" "X198105" "X198106" The 'X' prefix is returned. So, in general, it is safe to have column names with 'character' prefix instead of just numbers. Also, if we wanted to extract say '198101' column, we need a backtick

2023年3月21日 · Note that tibble::tibble(Statistics = x_names, Value = x_summary) provides the dataframe you are looking for, but be careful with the class of x_summary. data.frame(Statistics = x_names, Value = as.numeric(x_summary)) Statistics Value 1 Min. -9.000 2 1st Qu. 3.000 3 Median 5.000 4 Mean 17.625 5 3rd Qu.

2015年11月6日 · I'd like to change the column names using lapply: lapply (listDF, function(x) { colnames(x)[2:length(x)] <-todos[1:length(x)-1] } ) but this doesn't change the names at all. Am I not passing the data frames themselves, but something else? I just want to change names, not to return the result to a new object. Thanks in advance, p.