SinX是 正弦函数，而CosX是 余弦函数，两者导数不同，SinX的导数是CosX，而CosX的导数是 —SinX，这是因为两个函数的不同的升降区间造成的。 其它信息： sinx的导数是cosx (其中X是常数） 曲线上有两点 (X1,f（X1）), (X1+ x,f（x1+ x）).当 x趋向0时, y= (f（x1+ x）-f（x1）)/ x 极限存在，称y=f (X)在x1处可导，并把这个极限称f (x)在X1处的导数,这是可导的定义．. 增量 y=f (x+ x)-f (x) 不除 x．.

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

利用公式 ∫ udv = uv−∫ vdu ∫ u d v = u v - ∫ v d u 来分部求积分，其中 u = x u = x， dv = sin(x) d v = sin (x)。 x(−cos(x))−∫ −cos(x)dx x (- cos (x)) - ∫ - cos (x) d x. 由于 −1 - 1 对于 x x 是常数，所以将 −1 - 1 移到积分外。 x(−cos(x))−−∫ cos(x)dx x (- cos (x)) - - ∫ cos (x) d x. 化简。 点击获取更多步骤... x(−cos(x))+∫ cos(x)dx x (- cos (x)) + ∫ cos (x) d x.

The integral of x sin x gives the function to determine the area under the curve of the function f(x) = x sin x. The integration of x sin x is equal to −x cos x + sin x + C and it can be evaluated using the method of integration by parts (also known as the ILATE rule OR product rule of integration). Mathematically, we can write the integral ...

2024年12月16日 · Ex 7.6, 7 (Method 1) 𝑥 sin^(−1)⁡𝑥 ∫1 〖𝑥 〖𝑠𝑖𝑛〗^(−1) 〗 𝑥 𝑑𝑥 Let x = sin⁡𝜃 dx = cos⁡𝜃 𝑑𝜃 Substituting values, we get ∫1 〖𝑥 〖𝑠𝑖𝑛〗^(−1) 〗 𝑥 𝑑𝑥 = ∫1 〖sin⁡𝜃 〖𝒔𝒊𝒏〗^(−𝟏)⁡(𝒔𝒊𝒏⁡𝜽 ) cos⁡𝜃 𝑑𝜃" " 〗 = ∫1 〖sin ...

Examine how it acts on −x to find that f (x) = x−sin(x) is an odd function Explanation: A function f is ... In the diagram below (borrowed from this answer ), we have: \sin (\theta) < PQ, because …

函数 f(x) = x*sin(x) 的图像是一个连续波动的曲线。 下面是对该函数的图像描述： - 函数的图像在 x 轴上有无穷多个零点，即 f(x) = 0。

Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music…

y = xsin(x) y = x sin (x) 图像。 免费的数学问题解答者采用逐步解题讲解方式回答您的代数、几何、三角集合学、微积分以及统计学家庭作业问题，就像一位数学辅导老师那样为您提供帮助。

To solve a trigonometric simplify the equation using trigonometric identities. Then, write the equation in a standard form, and isolate the variable using algebraic manipulation to solve for the variable. Use inverse trigonometric functions to find the …