2018年3月13日 · See a full explanation below: The equation y = 0 describes a horizontal line. For each and every value of x; y has the same value of 0. By definition, a horizontal line has a slope of m = 0

I believe what @kutschkem is after is to avoid confusion, as the auxillary line that helps the spectator of his plots to keep track of x-coordinates is not placed at its customary place. Whether it is the customary place or the ruler itself that is referred to as the x-axis is not something I would brush off as trivial.

2. From the equation of the line. The slope of a line can also be determined from its equation. The standard form of the equation of a line is: #Ax^2+By+C=0# where #A,B and C# are some constants. First, the equation of the line must be written in the standard form. Then, the slope of the line = #-A/B#

The function is defined along the x-axis. It means that #y# is #0# in all values of #x# Answer link.

2016年6月16日 · It is the equation of the y-axis. It is a vertical line crossing the x-axis at the origin. All vertical lines have an equation in the form x = ... The number indicates the x-intercept. The line x = 0 is the equation for the y-axis. In the same way the equation of the x-axis is y=0

So, to find an equation of a line that is parallel to another, you have to make sure both equations have the same slope. In the general equation of a line #y=mx+b#, the #m# represents your slope value. An example of paralell lines would therefore be: (1) #y=mx+b# (2) #y=mx +c#. With #b# and #c# being any constants. Note that they have to be ...

2015年9月6日 · It's messy, but I got f(x) = 3/4x^4+(root(3)9)/4 We need: f'(x) = 3x^3, So we must have: f(x) = 3/4 x^4+C for some constant C. In order to be tangent to y=-x, we need an a with f'(a) = -1. Solving 3x^3=-1, we get x=-1/root(3)3. So we want y=-x to be tangent at a = -1/root(3)3. Now we find f(a) = f(-1/root(3)3) f(-1/root(3)3) = 3/4 1/(3root(3)3) + C = 1/(4root(3)3) = …

2023年1月3日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

2011年11月19日 · $\begingroup$ Anyway, another way to think of it: your $(x_0,y_0)$ and $(x_1,y_1)$ form a line segment. One could consider a perpendicular line segment passing through p, and it should also pass though the "reflected" point (why?) and the reflected point ought to have the same point-line distance as p (why?)... $\endgroup$ –