Jul 5, 2016 · The graph will be a horizontal line where all of the points have 2 as the value for y. Your equation is in slope intercept form, y=mx+b, where m is the slope and b is the y-intercept. The equation y=2 is in slope intercept form, where the slope is 0 and the y-intercept is 2. The equation can be graphed as the equation y=0x+2. The graph is a horizontal line where all …

Jul 7, 2015 · This is known as a difference of squares. It can be factored as: x^2 - y^2 = (x-y)(x+y) Notice that when you multiply (x-y) by (x+y) then the terms in xy cancel out, leaving x^2-y^2 ... (x-y)(x+y) = x^2+xy-yx-y^2 = x^2+xy-xy-y^2 = x^2-y^2 In general, if you spot something in the form a^2-b^2 then it can be factored as (a-b)(a+b) For example: 9x^2-16y^2 = (3x)^2-(4y)^2 = (3x …

Dec 3, 2014 · We can solve this problem in a few steps using Implicit Differentiation. Step 1) Take the derivative of both sides with respect to x.

Jul 22, 2015 · Step 1. Find the slope using the equation #m=(y_2-y_1)/(x_2-x_1)#, where #m# is the slope, and #(x_1,y_1)# and #(x_2,y_2)# are the two points on the line.

Feb 9, 2017 · There are 2 possible approaches. #color(blue)"Approach 1"# differentiate using the #color(blue)"chain rule"#. #color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx ...

Nov 12, 2014 · x^2+y^2=2x, which looks like: by plugging in {(x=rcos theta),(y=rsin theta):}, => (rcos theta)^2+(r sin theta)^2=2rcos theta by multiplying out, => r^2cos^2theta+r^2sin^2theta=2rcos theta by factoring out r^2 from the left-hand side, => r^2(cos^2theta+sin^2theta)=2rcos theta by cos^2theta+sin^2theta=1, => r^2=2rcos theta by …

Oct 17, 2016 · differentiate using the #color(blue)"power rule"#. #color(red)(bar(ul(|color(white)(a/a)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(a/a)|)))#

May 10, 2016 · divide terms on numerator by #x^2#. #rArry=x^(1/2)/x^2+x/x^2=x^(-3/2)+x^-1# now differentiate each term using the #color(blue)" power rule "#

May 19, 2018 · 32288 views around the world You can reuse this answer ...

Mar 11, 2018 · Given: Cartesian form #color(blue)(y = f(x) = x^2#. We must convert this into equivalent polar form.. To convert to polar form use