
If x^m * y^n = (x + y)^(m + n). Then how will you prove that …
Jul 24, 2017 · (my -nx)xy' = (my - nx)y :. xy' = y :. y' = y/x QED This assumes that where applicable the denominators are non-zero to permit the division to occur. Calculus Science
What is the derivative of x^n? - Socratic
Oct 10, 2014 · For the function f(x)=x^n, n should not equal 0, for reasons which will become clear. n should also be an integer or a rational number (i.e. a fraction). The rule is: f(x) = x^n …
y=sin(msin^-1x), then check whether or not (1-x^2)y_(n+2
May 10, 2018 · Here, #y=sin(msin^-1x)...to(1)# Diff.w.r.t. #x# #y_1=cos(msin^-1x)d/(dx)(msin^-1x)# #y_1=cos(msin^-1x)xxm/sqrt(1-x^2)#
If y=ln[x+sqrt(x^2+1)], check whether (1+x^2)y_(n+2) + (2n+1
Dec 13, 2017 · Please see a Proof given in the Explanation. Here, y_1,y_2,...,y_n denotes the forst, second,...,n^(th) derivative of y.
Differentiate y=x^n using first principle? - Socratic
Feb 19, 2018 · Differentiate y=x^n using first principle? Calculus. 1 Answer Shwetank Mauria Feb 19, 2018 #(dy)/(dx)=nx ...
If y varies directly as x, and y is 180 when x is n and y is n when x ...
Jun 25, 2017 · n = 30 Let's write a proportion to represent this problem! 1. When y = 180, x = n. If we write the value of y on the top and x on the bottom, one side of the proportion is: 180/n 2. …
Solve the Differential Equation #y'' - 4 y' + 4y = 2 e^(2x)#? - Socratic
Mar 17, 2017 · y_g = e^(2 x) ( x^2 + 2 x + 1 ) Method of Undetermined Coefficients Start with the homogeneous equation and the complementary solution : y'' - 4y' + 4y = 0 This has …
If x^m × y^n=(x+y)^(m+n) find dy/dx? - Socratic
Sep 3, 2017 · dy/dx = y/x We have: x^m y^n = (x+y)^(m+n) Take (natural) logarithms of both sides: ln(x^m y^n) = ln((x+y)^(m+n)) Then using the properties of logarithms we can ...
If y=acos (lnx)+bsin (lnx) then show that? x^2y^ ( (n+2 ... - Socratic
Apr 19, 2017 · We have poor notation as y_n is being used as the n^(th) derivative y^((n)), and logx is being used to represent the natural logarithm, lnx.
What is the #n^(th)# derivative of # y = x^(2n) - Socratic
Jan 16, 2018 · Let's have a look. Let y be a function of x, such that, y=f(x) :.color(red)(y=x^(2n)) Now, let y_n be the n^(th) derivative of the function y. :.y_1=2nx^(2n-1) :.y_2 ...