2014年9月4日 · 求sec 和 tan之间的公式1+tan^2 x=sec^2 x。 证明过程如下：（1）tan x = sin x/cos x（2）sec x =1/cos x（3）tan^2 x=sin^2 x/cos^2 x（4）1+tan^2 x=1+sin^2 x/cos^2 x=sec^2 x。

2014年7月26日 · Answer, y' = sec(tan(x))tan(tan(x))(sec2(x)) Solution : If, y = sec(f (x)) then using chain rule, y' = sec(f (x))tan(f (x))f '(x) In same way, y' = sec(tan(x))tan(tan(x))(tan(x))' y' = sec(tan(x))tan(tan(x))(sec2(x))

引个路，咱们首先画y=secx，不妨拿起笔和纸，尝试一下 注意最开始可以找图像上的几个点（结合sec和cos互为倒数），然后像线绳串珠子一样，画出大致的图像

2016年2月6日 · Use the product rule: y' = tanx d dx (secx) +secx d dx (tanx) You should know the identities: d dx (secx) = tanxsecx d dx (tanx) = sec2x Which gives... y' = tanx(tanxsecx) +secx(sec2x) Simplified: y' = tan2xsecx + sec3x

secx 是 正割 的意思， secx = \frac {1} {cosx} ，感觉本科期间知道下面两个 积分 就可以了。 \int_ {}^ {}secx*tanx dx = secx + C , \int_ {}^ {}secx*secx dx = tanx + C

y=tanx, 求 y' 解 y'= (tanx)'= (\frac {sinx} {cosx})'=\frac { (sinx)'cosx-sinx (cosx)'} {cos^ {2}x} =\frac {cos^ {2}x+sin^ {2}x} {cos^ {2}x} =\frac {1} {cos^ {2}x}=sec^ {2}x 即 (tanx)'=sec^…

Replace y' y ′ with dy dx d y d x. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

具体而言，它们是正弦、余弦、正切、余切、正割和余割的逆函数，并用于从任何角度的三角比获得角度。 反三角函数主要是三个： y＝arcsin (x)，定义域 [-1,1] ，值域 [-π/2,π/2] y=arccos (x) ，定义域 [-1,1] ， 值域 [0,π] y=arctan (x) ，定义域 (-∞,+∞)，值域 (-π/2,π/2)

Rewrite tan(x) tan (x) in terms of sines and cosines. Rewrite sec(x) sec (x) in terms of sines and cosines. Multiply by the reciprocal of the fraction to divide by sin(x) cos(x) sin (x) cos (x). Cancel the common factor of cos(x) cos (x). Tap for more steps... Convert from 1 …

2024年12月16日 · Ex 5.2, 4 Differentiate the functions with respect to x sec (tan ( √𝑥 )) Let 𝑦 = sec (tan √𝑥 ) We need to find Derivative of 𝑦 i.e. 𝑦’ = (sec⁡〖〖 (tan〗⁡√𝑥)〗 )^′ = 〖𝐬𝐞𝐜 〗⁡〖 (𝐭𝐚𝐧⁡√𝒙)〗 〖𝐭𝐚𝐧 〗⁡〖 (𝒕𝒂𝒏⁡√𝒙)〗 (tan⁡√𝑥 )^′ = 〖sec ...