2018年2月27日 · The given expressions are very different. Consider the case A=pi/2, then: sin 2A = sin pi = 0 2sin A = 2sin (pi/2) = 2 We cannot solve expressions (only equations), so the given expression has no "solution"

2020年8月29日 · prove that: sin2A +sin2A. tan2A =tan2A - 21780616

Click here👆to get an answer to your question ️ solvesin 2a cos 2a

If sin A + sin 2 A = 1, then the value of cos 2 A + cos 4 A is (a) 2 (b) 1 (c) −2 (d) 0. View Solution. Q3

2018年2月22日 · a\ =\ -\frac{1}{2}sin^{-1}(\frac{3}{4}) sin(2a)=-\frac{3}{4} By taking inverse function on both sides, 2a =sin^{-1}(-\frac{3}{4}) Divide both sides by 2: a\ =\ \frac ...

2015年6月5日 · Use the trig identity cos (a + b) cos ( a + a) = cos a.cos a - sin a.sin a = cos^2 a - sin^2 a

2018年5月21日 · We need the crudest cosine double angle formula: #cos(2A) = cos(A+A) = cos^2 A - sin ^2 A # #sin(2A) = sin(A+A) = 2 sin A cos A #

Click here:point_up_2:to get an answer to your question :writing_hand:prove that cos 4a cos 2a sin 4a sin 2a

2018年2月21日 · Please see below. Probably you mean if sin^2A+sin^4A=1, then tan^2A-tan^4A=1. The proof is as follows: sin^2A+sin^4A=1 hArrsin^4A=1-sin^2A=cos^2A or sin^2A/cos^2A=1/sin^2A or tan^2A=csc^2A or tan^2A=1+cot^2A multiplying each term by tan^2A we get tan^4A=tan^2A+1 or tan^4A-tan^2A=1

2017年1月28日 · sin2a=2sinacosa sin2a can be written as sin(a+a) and using sum identity for sine i.e. sin(A+B)=sinAcosB+cosAsinB this becomes sin(a+a)=sinacosa+cosasina = sinacosa+sinacosa = 2sinacosa Trigonometry Science