2021年6月26日 · And in the similar problem I found here: Hard time understanding assembly language it seems that with 260 (%rcx, %rdx) we needed to convert the value to hexadecimal? But that didn't work for 9 (%rax, %rdx). Same with (%rax, %rdx,4). I still get 112. How does that lead to address 0x10C to get a value of 0x11?

2012年2月27日 · The result of this instruction will be whatever dword is stored at the address 0x10c multiplied by 16 (or, if you prefer, shifted to the left by 4 bits). The result will be written to that address as well.

2013年2月16日 · You don't multiply 0x10C by 16, you multiply what's at address 0x10C, which is 0x11, by 16. And that gives you 0x110 (or 272).

0x104 refers to the value at address 0x104. $0x108 refers to the constant value 0x108. (%eax) refers to the value at address EAX, which is equivalent to 0x100 (=0xFF). 4(%eax) refers to the value at address EAX+4, which is at 0x104. 9(%eax, %edx) refers to the value at address EAX+9 + EDX, which is at 0x10C.

The simple version is 0x is a prefix denoting a hexadecimal number, source. So the value you're computing is after the prefix, in this case 10. But that is not the number 10. The most significant bit 1 denotes the hex value while 0 denotes the units. So the simple math you would do is 0x10 1 * 16 + 0 = 16 Note - you use 16 because hex is base 16. …

2022年3月7日 · 0x10C 0x11 | I understand that in some cases you are supposed to add up the values of registers, while they are in hexadecimal form, such as the following.

2015年1月17日 · With my calculations I was able to find the r1 correctly but after that I fail.For example the r2 come out 0x05 and at the end r0 come out 0x10C how can this be,there is no code here to save the r0 on to the memory why it changes.I guess my dont know what to do with r2 and r4.Anyone has knowlage about ARM help will be really good.

2022年2月16日 · The problem is on page 218 of chapter 3: Practice problem 3.1: Assume the following values are stored at the indicated memory addresses and registers: Address value register value 0x100 0xFF %rax 0x100 0x104 0xAB …

2018年9月28日 · I'm reading this book and I can't find an answer to the following question. Assume the following values are stored at the indicated memory addresses and registers: 0x100 = 0xFF; 0x104 = 0xAB; 0x10...

2015年4月28日 · @tjnapster555 [bx+12] is the same as [0x10c], mov ax,[0x10c] moves the word located at address 0x10c into register ax. mov ax, 0x10c moves the value 0x10c into register ax. 0xc is hexadecimal for 12