We know that 0xaa and 0x55 are hexa-decimal representation . Moreover each character in hexadecimal is represent using 4bits. so , 0xaa is equivalent to 1010 1010 (since, a = 1010 in …

2014年9月29日 · I am surprised by C++'s behavior when applying bit-wise not to an unsigned char. Take the binary value 01010101b, which is 0x55, or 85. Applying bit-wise not on an eight …

2021年9月26日 · .byte 0x55 .byte 0xaa so people sometimes refer to the signature in that manner. Share. Improve this answer.

2015年1月27日 · I can only use the bitwise operators mentioned below to create the described function: /* * allEvenBits - return 1 if all even-numbered bits in word set to 1 * Examples …

2018年9月21日 · Magic number is a word of 0xaa55 not a word of 0x55aa. A word is 16-bits (2 bytes). Because the x86 processors are little endian they are stored in memory as the byte …

2016年10月11日 · There is nothing magical or mystical about that combination. Implementers needed a means by which to determine if the first sector of a device was bootable (boot …

2018年12月25日 · The boot signature is ALWAYS a 0x55 byte followed by a 0xaa byte. How you display it in a debugger or dump utility may be different if they output the data as WORD's …

2013年7月23日 · 0x65 && 0x55 Since both operands 0x65 and 0x55 evaluate to true the whole expression evaluates to true and thus expands to 1, which applies to c99 but other answers in …

Finally, 0xAA is 10101010 and 0x55 is 01010101. When these masks and shifts are done, the result is: 76543210 Voila! this is the reversed order. Notice that for each pair of shifts, the bit …

2014年1月15日 · 0x55 = 01010101 0x33 = 00110011 0x0f = 00001111 0xff = 11111111 Let's go with an 8 bit example: a = 01101010. a & 0x55 = 01000000; (a >> 1) & 0x55 = 00010101 If we …