1 is greater than 0. So we call recursion(0). Nothing printed yet. 0 is not greater than 0, so we return 0. We don't print anything here; So for recursion recursion(1) we got 1 + 0 (from previous line) so we print 1 and return 1; For recursion(2) we got 2 + 1 (from previous line) so we print and return 3; For recursion(3) we got 3 + 3 so we ...

All I need is a for loop that'll print specific numbers from a given range. I was thinking of starting off with a basic for loop and it'll print the whole range, but I only need numbers 1, 3, 6, 1...

How can I find summation formula for the sequence : :0,1,3,6,10,15,...,n please take care the first element is 0 .

time_interval = [4, 6, 12] I want to sum up the numbers like [4, 4+6, 4+6+12] in order to get the list t = [4, 10, 22].

WAP in Python to generate the following series upto 500. #1, 3, 6, 10, 15, 21,... 1+2=3,3+3=6,6+4=10,10+5=15.

I'm working on Problem #12 for Project Euler, which goes as follows: The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + ...

2014年6月24日 · Assert position at the beginning of the string «^» Match a single character in the range between “a” and “z” «[a-z]{1}» Exactly 1 times «{1}» Match a single character present in the list below «[a-z0-9_]{3,13}» Between 3 and 13 times, as many times as possible, giving back as needed (greedy) «{3,13}» A character in the range between “a” and “z” «a-z» A character in ...

2022年6月5日 · For example, if I call this function with the input of [1,2,3,4], the output should be [1,3,6,10]. However, when I run my code, it returns an empty array. The following is the code I got so far.

2015年11月2日 · I'm looking form a programatic way to take an integer sequence and spit out a closed form function. Something like: Given: 1,3,6,10,15 Return: n(n+1)/2 Samples could be useful; the language is

0,1,3,6,10,15,21,... each term gets incremented in the order of natural numbers I tried to generate the nth of the series but ended with TLE here's my code . s=0 for(int i=1;i<=n;i++) s=s+(i-1); Can any anybody help me with a better algorithm.