x(x+1) is WRONG! It means a function x of x-1. x*(x-1) is right. Use the ^ (caret) for exponentiation. x^2 means x squared. x/2y means Resources: Simplifier Portal, help with entering simplifier formulas (a must read).

If sin(x)=-5/13 and x is in quadrant III,... So for angle x, we have a 5-12-13 right triangle in quadrant III, where x =-12, y=-5, and r=+13. There is often a conflict of notation when x is used for an angle, and also for values of the adjacent side of the defining right triangle. There is a problem here. But I think you won't get confused.

You can put this solution on YOUR website! The prime factorization of "k!" is .The value for "k" is

You can put this solution on YOUR website! if csc(theta)=13/5 and theta is in the second quadrant, what is sec(theta)?

We plot the point (11,7) and draw the horizontal line y = -5, all of whose points are (x, -5) for different values of x. Then we take a compass, open it up to 13 units, and with the sharp point on (11,7), we swing an arc that cuts the horizontal line in two places: Then we draw radii (in green) from (11,7) to those two points.

the relationship between x and y is a function because each and every value of x results in one and only one distinct value of y. in function notation, y = .13 * x is written as f(x) = .13 * x f(5) replaces x with 5 to get f(5) = .13 * 5 = .65 it tells you to evaluate the function when x = 5. x = 5 means you printed 5 digital pictures.

Question 413529: If cosx =4/5 and cos y =12/13,find sin (x+y) when x and y are the measures of two first quadrant angles Answer by jsmallt9(3758) ( Show Source ): You can put this solution on YOUR website!

You can put this solution on YOUR website! If sin x =12/13, where pi/2 = x = pi, determine: a) sin (x/2) b) sec (x/2)

Question 1195439: Assume that a procedure yields a binomial distribution with a trial repeated n = 30 times. . Use the binomial probability formula to find the probability of x = 5 successes given the probability p = 1/4 of success on a single tr

First we will distribute the 3 to both 13 and -3y. 39 - 9y + 5y = 19 Combine like terms. 39 - 4y = 19 Subtract 39 from both sides of the equation to isolate the y. -4y = -20 Isolate the y further by dividing both sides of the equation by -4. y = 5 Now we can substitute y in the first equation to find x. x + 3(5) = 13 x + 15 = 13 Isolate the x ...