2016年2月13日 · Use the quadratic formula to find: x^2+2x+18 = (x+1-sqrt(17)i)(x+1+sqrt(17)i) Quadratic Formula Method x^2+2x+18 is in the form ax^2+bx+c with a=1, b=2 and c=18. This has discriminant Delta given by the formula: Delta = b^2-4ac = 2^2-(4*1*18) = 4-72 = -68 = -2^2*17 Since this is negative, this quadratic expression has no Real zeros and no linear factors with …

First look for common factors #18x^2-2=2(9x^2-1)# then see if the bracket can be factorised. we note difference of squares hence

2018年1月19日 · (x-3)^2-18 x^2-6x-9 = (x^2-6x+9)-18 x^2-6x+9 = (x-3)(x-3) = (x-3)^2 (x-3)^2-18 = (x^2-6x+9)-(9+9) = x^2-6x+9-9-9 = x^2-6x-9

(3 sqrt2)/x sqrt [(3*3*2)/(x.x)] = 3/x sqrt2

2015年10月18日 · (x^2 + 3x − 18) / (x^2 − 36) = (x - 3) / (x - 6) only if x != -6 x^2 + 3x − 18 can be written as (x + 6) * (x - 3) and x^2 − 36 can be written as (x + 6) * (x ...

2016年4月2日 · #x^2=(-1)xx3^2xx11# Take the square root of each side. #x=+-sqrt((-1)xx3^2xx11)# #=> x=+-3xxsqrt(11)sqrt(-1)# But #sqrt(-1)=i# #color(blue)(=>x=+-3isqrt(11))# '~~~~~ Notice that the graph does not cross the x-axis. But by writing the equation as #x^2+18=-81# #y=x^2+99# So to solve for #x# we have to write. #y=0=x^2+99# but for #y=0# implies ...

y = 3x + 1, y = #x^2+3x + 2#, and y = #x^3#. Do you notice that each one of those functions has powers of x that are Whole numbers? Stick with those, and you will have a polynomial. All polynomials have a domain of "All Real Numbers". In interval notation, we write: #(-\infty,\infty)#. On the horizontal number line, that covers all numbers from ...

2016年6月1日 · x^2+18x+81=(x+9)^2 As 81 is the square of 9 and middle term 18 is double of this number, (compare it with ...

2018年3月23日 · What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72?

2016年8月21日 · (x^2 -3x -18) div (x-6) = x + 3, "rem " 0 The method is easy, but the format is difficult to show. I'll do my best.