
How do you solve for y in #x-2y=2#? - Socratic
2016年5月28日 · y=x/2-1 color (brown) ("When you see a question of this type ")your objective is to end up with something like y="'something'". You do this in stages. First isolating all the …
How do you factor x^2 - y^2 ? + Example - Socratic
2015年7月7日 · This is known as a difference of squares. It can be factored as: x^2 - y^2 = (x-y) (x+y) Notice that when you multiply (x-y) by (x+y) then the terms in xy cancel out, leaving x^2 …
How do you factor xy-2y-x+2? | Socratic
2018年4月16日 · factor the terms by grouping ⇒ y(x −2)−1(x − 2) take out the common factor (x −2) = (x −2)(y − 1) ⇒ xy − 2y −x +2 = (x − 2)(y − 1)
How can I solve this differential equation? x dy/dx+y=x^2y^2
2018年2月18日 · This equation is a Bernoulli equation as it can be rewritten to the form dy dx + f (x)y = g(x)yn. From x dy dx + y = x2y2, one can divide both sides by x so that it fits the …
How do you differentiate e^ (x^ (2)y) = 2x + 2y? | Socratic
2015年5月24日 · Take one side at a time. Let f (x, y) = e^ (x^2y). [ (df)/ (dx)]_"left" = (e^ (x^2y)) [x^2 (dy)/ (dx)+y*2x] (chain rule, product rule) [ (df)/ (dx)]_"right" = 2 + 2 ...
How do you find ( (d^2)y)/ (dx^2)? - Socratic
2016年11月3日 · Defining f (x,y(x)) = 2xy(x) + 2y(x)2 − 13 = 0 then df dx = 2y +2xy' +4yy' = 0 and d dx df dx = 4y' +2xy'' + 4y'2 +4yy'' = 0 after substitution of y' we have y'' = 2xy + 2y2 (x + 2y)3 …
Implicit Differentiation - Calculus | Socratic
Implicit differentiation allows differentiating complex functions without first rewriting in terms of a single variable. For example, instead of first solving for y=f(x), implicit differentiation allows …
How do you factor x^2-xy-2y^2? | Socratic
2016年7月29日 · x2 −xy − 2y2 = x2 −2xy +xy − 2y2 = x(x −2y) +y(x − 2y) = (x +y)(x − 2y)
How do you find the slope of the following line, x+2y= -2
2015年4月1日 · I would rearrange the equation to actually "see" the slope, as: 2y=-x-2 y=-x/2-2/2 y=-1/2x-1 The slope is the numerical coefficient in front of your x, i.e., -1/2
How do you graph using the intercepts for - 2y = -2? | Socratic
2015年11月9日 · The x and y intercepts give us two points on the line defined by the linear equation. The x-intercept is the value of x when y = 0 (for all points on the X-axis y = 0) Given …