2013年2月12日 · It seems that diborane (see answer by feetwet) is the only compound rated with H4 F4 R4 code by NIOSH, though there are two substances lacking just a single point to join a 4-4-4-club: picric acid $\ce{(O2N)3C6H2OH}$: NFPA 704 3-4-4 ;

2019年6月27日 · $\ce{[Ni(CN)4]^2-}$ is a low spin , inner orbital complex having $\mathrm{dsp^2}$ hybridisation. According to Crystal Field Theory, $\ce{CN^-}$ is a strong field ligand that causes pairing of elect...

2019年5月19日 · Dichlorobis(triphenylphosphine)nickel(II), or $\ce{NiCl2[P(C6H5)3]2}$ in square planar form is red and diamagnetic.

2020年9月10日 · When naming a organic compound, S/R-notation comes if there is a chiral atom present.The S/R-notation always accompanies a numerical such as (2S,3R)- where the numerical refers to the chiral carbon position in the molecule according to the IUPAC numbering while R and S representate the orientation of the chiral atom according to the Cahn–Ingold–Prelog priority …

2019年5月22日 · Consider the following compounds: Cyclopenta-2,4-dien-1-one Cyclopent-2-en-1-one In both compounds, I can visualize a resonating structure in which the ring follows Huckel's rules by: The $\\ce{C...

2016年12月17日 · My textbooks states the Drago's rule in inorganic chemistry as follows:. The more electronegative atom prefers the orbital having more $\mathrm{p}$ character, and lone-pairs or less electronegative elements prefer such orbitals, as have more s character.

2014年10月12日 · By sand I'd guess you mean $\ce {SiO2}$. You see, sand or $\ce {SiO2}$ for what it matters, don't appear in nature as single molecules, they're crystals and the crystal arrangement defines if it will be quartz, sand, silica-gel and other stuff, and this crystalline structure also defines it's solubility in water.

Larger the difference in electronegativities of bonded atoms, the larger the dipole moment. (this statement has been extracted from chemwiki-dipole moment) The electronegativity difference between

2016年10月11日 · Sulfuric acid, $\ce{H2SO4}$, having an enthalpy of formation of $-814\ \mathrm{kJ/mol}$, is quite stable and won't decompose easily.

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