2018年4月8日 · (x-1)^4 -= x^4 -4 x^3 + 6x^2- 4x+1 We can expand the expression using the binomial theorem: (x-1)^4 -= sum_(r=0)^4 ( (n), (r) ) (x)^r(-1)^(n-r) " " = ( (4), (0) ) (x ...

2015年5月10日 · x^4 + x^2 + 1 = (x^2 + x + 1)(x^2 - x + 1) To find this, first notice that x^4 + x^2 + 1 > 0 for all (real) values of x. So there are no linear factors, only quadratic ones. x^4 + x^2 + 1 = (ax^2 + bx + c)(dx^2 + ex + f) Without bothering to multiply this out fully just yet, notice that the coefficient of x^4 gives us ad = 1. We might as well let a …

2018年5月2日 · x^4+4x^3+6x^2+4x+1 The binomial theorem states: (a + b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4 so here, a=x and b=1 We get: (x+1)^4 = x^4+4x^3(1)+6x^2(1)^2+4x(1)^3+(1)^4 (x+1)^4 = x^4+4x^3+6x^2+4x+1

2017年3月2日 · How do you use the binomial series to expand #1 / (1+x)^4#? How do you use the binomial series to expand #f(x)=(1+x)^(1/3 )#? See all questions in The Binomial Theorem

2017年11月30日 · The value of x. Solution: To answer this question, we should know some of the properties of exponents and powers. Now, As given, we have, After taking 4 with power x common, we have, (On taking 4 as LCM) As the base is the same, so, on comparing the powers, we have, Hence, the value of x is 5/2 or 2.5.

2018年4月18日 · x^4-1=(x^2+1)(x+1)(x-1) using complex numbers x^4-1=(x+ib)(x-ib)(x+1)(x-1) we make use of the difference of squares a^2-b^2=(a+b)(a-b) x^4-1=(x^2+1)(x^2-1) we can use dos for the second bracket once more x^4-1=(x^2+1)(x+1)(x-1)--(1) for real numbers we can proceed no further, but if we use complex numbers note" "i^2=-1 we see a^2+b^2=a^2-(ib)^2=(a+ib)(a-ib) (1)rarrx^4-1=(x+ib)(x-ib)(x+1)(x-1)

2016年9月3日 · 1 or -1 (2x-1)(2x+1)=0 2x-1=0,2x+1=0 2x=0+1,2x=0-1 2x=1,2x=-1 x=1/2,x=-1/2 S.S{+1/2,-1/2} #color(green)("You only need to solve as a quadratic if you have a "bx)# #color(green)("term in the standard form of "y=ax^2+bx+c)#

The quotient rule is used to determine the derivative of one function divided by another.

2014年7月31日 · Ex: 2x^2+4 , (1,6) credit: www.wolframalpha.com Using the power rule for derivatives, we end up with 4x as the derivative. Plugging in our point's x-value, we have: 4(1) = 4 This tells us that the slope of our original function at (1,6) is 4, which also represents the instantaneous rate of change at that point.

2018年7月8日 · What is the domain and range of #F(x) = 1/ sqrt(4 - x^2)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function. 1 Answer