
[FREE] What are the solutions to the quadratic equation 40 - x^2
2016年7月27日 · To solve the quadratic equation 40 − x 2 = 0, we first rearrange it to the standard form of a quadratic equation, which is a x 2 + b x + c = 0. In this case, we can rewrite it as x 2 = 40. Next, we take the square root of both sides: x = ± 40 Calculating 40 , we can simplify it: 40 = 4 × 10 = 2 10 Thus, we have x = ± 2 10 . To find the ...
[FREE] Given the function f(x) = (x-2)^3 + 40, it is rotated clockwise ...
x − 2 = 3 − 40 x = 2 + 3 − 40 x ≈ 2 − 3.42 ≈ − 1.42 Step 3: Find the intercepts Now, we check where the original graph intersects the x-axis. Setting f ( x ) = 0 gives us the same equation, which indicates that the x-intercepts we will work with from the original function are at …
[FREE] Given f(x) = x^2 + 14x + 40 . Enter the quadratic function in ...
2018年3月5日 · To convert the quadratic function f (x) = x 2 + 14 x + 40 into vertex form, we need to complete the square. The vertex form of a quadratic function is given by f (x) = a (x − h) 2 + k, where (h, k) is the vertex of the parabola. Start by rewriting the function: f (x) = x 2 + 14 x + 40. Isolate the constant term: f (x) − 40 = x 2 + 14 x ...
[FREE] A concrete block has a volume of 40 cubic meters and the ...
2024年12月10日 · x = 0: Generally, having a dimension of zero would result in a volume of zero, which wouldn’t match the given 40 cubic meters, so this option is less likely to be correct. Conclusion: Given the constraints and options, the values x = − 2 and x = 2 are consistent with solutions typically needed to reach a specific volume under similar ...
[FREE] What are the solution(s) to the quadratic equation 40 - x^2 …
2019年10月8日 · For example, if we choose x = 2 10 , we can substitute back into the original equation to verify: 40 − (2 10 ) 2 = 40 − 40 = 0, confirming that our solution is correct. Similarly, for x = − 2 10 , the calculation yields the same outcome because squaring a negative number gives a …
What is the quotient and remainder, written as partial fractions, of
To find the quotient and remainder using partial fractions, we first perform polynomial long division to divide 2x^3 - 25x + 40\) by \(x^2 + 2x - 8\ The division looks like this: 2 x + 6. x 2 + 2 x − 8∣2 x 3 − 25 x + 40 − (2 x 3 + 4 x 2 − 16 x) − 29 x + 40 − (− 29 x − 58) 98. So, 2x^3 - 25x + 40 = (2x + 6)(x^2 + 2x - 8) - 29x ...
[FREE] Divide the polynomial 12x^4 + 17x^3 + 8x - 40 by x + 2 ...
2017年7月31日 · The polynomial 12 x 4 + 17 x 3 + 8 x − 40 divided by x + 2 yields a quotient of 12 x 3 − 7 x 2 + 14 x − 20 with a remainder of 0. This means the division is exact with no leftover term. This means the division is exact with no leftover term.
Which of the following correctly shows the regrouping for 45 x 12?
The correct representation of the** re-grouping f**or 45 x 12 is: 40 x 10; 5 x 10; 40 x 2; 5 x 2. This method is a way of breaking the** multiplication **down to enable easier calculation: 40 x 10 is 400, 5 x 10 is 50, 40 x 2 is 80 and finally 5 x 2 is 10. If you add all these together (400 + 50 + 80 + 10), you get 540 which is the result of 45 ...
[FREE] What are the solution(s) to the quadratic equation 40 - x^2 …
2018年6月22日 · For example, if we substitute x = 2 10 back into the original equation, we should verify that it equals zero: 40 − (2 10 ) 2 = 40 − 40 = 0 This proves that 2 10 is indeed a solution. The calculations performed above use standard algebraic manipulations for solving quadratic equations, confirming that the mathematical steps taken are correct.
Find the vertex, focus, directrix, and focal width of the parabola.
2017年7月13日 · − 40 1 x 2 = y. we can start by rewriting it in a standard form. Rearranging the equation, we have: y = − 40 1 x 2. This shows us that the parabola opens downwards since the coefficient of x 2 is negative. The standard form of a parabola that opens downwards is given by: y = − 4 p 1 x 2. where (h, k) is the vertex, (h, k + p) is the focus ...