2020年2月24日 · 4HCl(aq) + MnO 2 (s) ==> MnCl 2 (aq) + 2H 2 O(l) + Cl 2 (g) ... balanced equation (re-dox reaction) moles HCl present = 44.3 g x 1 mol/36.46 g = 1.215 moles HCl. moles MnO 2 present = 41.9 g x 1 mol/86.94 g = 0.4819 moles MnO 2. Since the mol ratio in the balanced equation is 4 HCl to 1 MnO 2, the HCl is LIMITING.

2021年11月5日 · Kaitlyn, Before you can do any calculations, you must have a correctly balanced equation. This is a redox reaction which can be seen by the fact that Mn goes from 4+ on the left side to 2+ on the right side, and Cl goes from 1- on the left to zero on the right.

2021年10月18日 · 4HCl(aq) + MnO 2 (s) ==> MnCl 2 (aq) + 2H 2 O(l) + Cl 2 (g) ... balanced equation. An easy way to find the limiting reactant is to simply divide the moles of each reactant by the respective coefficient in the balanced equation.

2019年7月26日 · Consider the reaction. 4HCl(g) + O 2 (g) 2H 2 O(g) + 2Cl 2 (g) Using the standard thermodynamic data in the tables linked above, calculate G for this reaction at 298.15K if the pressure of each gas is 14.28 mm Hg.

2017年12月3日 · Consider the reaction between HCl and O2: 4HCl(g)+O2(g)→2H2O(l)+2Cl2(g) When 63.1 g of HCl are allowed to react with 17.2 g of O2, 46.1 g of Cl2 are collected. A. Determine the limiting reactant for the reaction.

2023年11月30日 · XCl4(s) + O2(g) + 2H2(g) ==> XO2(s) + 4HCl(g) To get rid of O2(g) and H2(g) on the left, we can reverse equation (1) and multiply by 2. 2H2O(g) ==> 2H2(g) + O2(g) ... ∆H = +483.6 kJ. Add this to the above and we have... XCl4(s) + 2H2O(g) ==> XO2(s) + 4HCl(g) And finally, to convert the H2O(g) to H2O(l), reverse equation (5) and add it to the ...

2018年3月8日 · 4HCl+O2 <=>2Cl2+2H2O (all gases) Equal numbers of moles of HCl and O2 in a closed system are allowed to reach equilibrium as represented by the equation above. Which of the following must be true at equilibrium?

2020年11月11日 · 7. 4HCl(aq)+MnO2(s) MnCl2(aq)+2H2O(l)+Cl2(g) A sample of 40.3 g MnO2 is added to a solution containing 50.5 g HCl. (a) If the yield of the reaction is 87.1% what is the actual yield of chlorine? (b) Identify the theoretical yield of Cl2

2020年10月31日 · Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described by the chemical equation MnO2(s)+4HCl(aq) MnCl2(aq)+2H2O(l)+Cl2(g) How much MnO2(s) should be added to excess HCl(aq) to obtain 285 mL Cl2(g) at 25 °C and 705 Torr ?

2021年11月25日 · CH 4 (g) + 4Cl 2 (g) CCl 4 (g) + 4HCl(g) ... balanced equation. Bond breaking requires energy. Bond formation releases energy. So, take the difference in bond energy of reactants (bond breaking) and that of the products (bond forming) to get the ∆H of reaction. Bond energy of reactants: C-H bond x 4 = bond energy for CH 4