2016年8月12日 · 52/8 = 6 with a remainder of 4 A quotient is the answer to a division operation. 52/8 = 6 with a remainder of 4 6xx8 = 48 and 52-48 = 4 52/8 can also be shown as a mixed number which shows a whole number and the remainder as a fraction of 8. 52/8 = 6 4/8 = 6 1/2" "larr simplest form

2016年4月2日 · We want the energy change for the transition: H_2O(s) rarr H_2O(l), at 0""^@ C. The latent heat of fusion of water is 333.55 J*g^-1. This is actually exceptionally large, and reflects the strength of hydrogen bonding as an intermolecular force. So, the heat required to melt the given quantity of water, under the given conditions is, 333.55 J*cancel(g^-1) xx 52.8 cancelg = …

2015年4月15日 · I would take the 52 to the right: sqrt(-x)=8-52 Square both sides: (sqrt(-x))^2=(-44)^2 -x=1936 x=-1936 BUT this solution, plugged back into your original equation, DOES NOT WORK. I think your equation doesn't have REAL solutions.

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2018年3月16日 · (32/52) In a deck of cards, half of the cards are red (26) and (assuming no jokers) we have 4 jacks, 4 queens and 4 kings (12). However, of the picture cards, 2 jacks, 2 queens, and 2 kings are red. What we want to find is "the probability of drawing a red card OR a picture card" Our relevant probabilities are that of drawing a red card or a picture card. P(red)=(26/52) P(picture)=(12/52) For ...

2016年11月15日 · 2/13 There are 52 cards in a standard deck: 13 ordinal cards (Ace - 10, Jack, Queen, King) and 4 of them - one to each suit (hearts, diamonds, clubs, spades) and so we have 4xx13=52. There are 8 cards that fit the question (4 each of aces and kings). And so in a random draw, the odds of drawing one of those 8 cards out of the total number of 52 is: 8/52 which we can simplify: 8/52=2/13

2017年1月13日 · There is a 50% chance that the card drawn will be red. Red cards make up 50% of the deck. 26/52 = 1/2 Therefore, if you're drawing one card, there is a 50/50 chance that the card will be red.

2018年6月9日 · The numbers are: 7, 15 and 30 First write an expression for each of the three numbers, We know the relationship between them so we can use one variable. Choose x as the smallest one. Let the first number be x The second number is x+8 The third number is 2(x+8) Their sum is 52 x+x+8+2(x+8)=52 x+x+8+2x+16=52 4x +24 = 52 4x = 52-24 4x = 28 x=7 The numbers are: 7, 15 and 30 Check: 7+15+30 = 52

2016年2月15日 · P("ace or 9") = 2/13 There are two possible events that could happen. Either you draw an ace or a 9. There are four aces in a deck of 52 cards as well as 4 of 9's in the same deck. The conjunction "or" implies adding up the probabilities of the individual events . Thus, P("ace or 9") = 4/52 + 4/52 = 8/52 Reduced to lowest terms, the answer is equivalent to 2/13

What is x-intercept? It is such an argument (x-value) where y-value equals 0. In equations you would tell that it is root of the equation.