What is 7 + 7÷7 + 7×7 - 7 = ? This problem has been shared on Facebook and Twitter millions of times and confused many people. In this video, I present two d...

$7^4 = 2401 \equiv 1 \pmod{100}$, so you only need to calculate $7^{7^{7^{7^{7^7}}}} \pmod{4}$. We know that $7 \equiv -1 \pmod 4$ and $7^{7^{7^{7^7}}}$ is odd, so $7^{7^{7^{7^{7^7}}}} \equiv -1 \equiv 3 \pmod 4$, and then $$7^{7^{7^{7^{7^{7^7}}}}} \equiv 7^3 \equiv 43 \pmod {100}$$

2011年10月18日 · I've used modular exponentiation on 7^7 to find the last digit is 3. How can I use that fact to find the last digit of 7^7^7? (7 to the power of 7, to the...

2017年5月13日 · What is the calculation way to find out the last $2$ digits of $7^{7^{7^7}}$? WolframAlpha shows $...43$.

A big hint: the powers of $7$, $7^x$, are periodic mod $10$; since $7^4 \equiv 1 \pmod{10}$, every $4$th power of $7$ will end in the same digit; this means that you only need to find out what $7^{7^{7^7}}$ is mod $4$.

2015年3月30日 · The answer is: 7. This is because: 7^7=a it's a number whose last digit is 3. a^7=b it's a number whose last digit is 7. b^7=c it's a number whose last digit is 3. c^7=d it's a number whose last digit is 7. d^7=e it's a number whose last …

2016年11月3日 · One way to see this is to translate the expression 7 + 7 ÷ 7 + 7 × 7 – 7 = into a situation about money. The expression begins with 7, so you start out with $7. The next part is “+ 7 ÷ 7.” This means you get a 1/7 share of $7. Since a 1/7 share of $7 is $1, that means you get $1. At this point you have $7 + $1 = $8.

#Shorts Hi, In this video I'll be looking to find the last digit of 7^7^7 when written in base 10. To solve this I'll be using modular arithmetic, and exploiting periodic patters in powers of...

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Answer: 7 to the power of 7 is 823543. Let's simplify the above question by using rules of exponents and powers. Explanation: Given: 7 to the power of 7. The rules for exponentiation states that if m is a positive integer and k is any real number, then k m can be represented as: k m = k × k × … × k (m times)