
How do you solve #81^x = 27^(x + 2)#? - Socratic
2015年7月22日 · More simply, x=6 (logarithms are unnecessary in this case). 81=3^{4} and 27=3^{3}, so this equation can also be written as 3^{4x}=3^{3(x+2)}=3^{3x+6}. Since the bases …
What is 81 degrees Fahrenheit In Celsius? - Answers
2024年11月6日 · So, to convert 81 degrees Fahrenheit to Celsius: (81 - 32) x 5/9 = 49 x 5/9 = 245/9 ≈ 27.22 degrees Celsius. Therefore, 81 degrees Fahrenheit is approximately 27.22 …
How do you solve (x+5)^4 = 81? - Socratic
2016年3月25日 · Take the 4th root of both sides to undo the 4th power on (x+5)^4. root4((x+5)^4)=root4 81 Note that 81=3^4. Thus, root 4 81=+-3. This is one of the trickier parts …
What is 52 * 81? - Socratic
2016年4月9日 · 81 x 52 . then the first number is 2 x 81, put directly below the numbers, and the second number is 5 x 81 placed under the first calculation, shifted one column to the left. …
If 81^x=729, find x? - Socratic
2017年9月24日 · x=1.5 As 81^x=729, we can write it as (3^4)^x=3^6 or 3^(4x)=3^6 Hence 4x=6 and x=6/4=1.5
Simplification of Radical Expressions - Algebra - Socratic
#2sqrt5 × 3sqrt10 = 2 × 3sqrt(5×10)=6sqrt50# #= 6sqrt(2·5^2)# # = 30sqrt2# Now if you want to divide, then the coefficients are divided among themselves and sub-radical amounts each …
How do you solve sqrt( 9x+81)= x+5? - Socratic
2016年4月26日 · 7 and -8 Square both sides --> 9x + 81 = (x + 5)^2 = x^2 + 10 x + 25. x^2 + x - 56 = 0. Solve this quadratic equation by using the new Transforming Method (Socratic …
How do you solve #243^(.2x)=81^(x+5)#? - Socratic
2016年3月11日 · x = -20 /3 243 ^(.2x) = 81^ (x+5) Simplifying the bases by prime factorisation: 243 =3*3*3*3*3 =color(blue ...
How do you solve 3^(x-1)=81? - Socratic
2016年7月15日 · x=5 As 3^(x-1)=81, we have x-1=log_(3)81=log_(3)3^4 = 4log_(3)3=4×1=4 Hence x=4+1=5. In this example, the fact that #81 # is one of the powers of #3,# allows us to …
How do you solve 81/33 = x/5.5? - Socratic
2016年2月17日 · How do you solve #81/33 = x/5.5#? Algebra. 1 Answer Binayaka C. Feb 17, 2016 #x=13.5# Explanation: #x=5.5 ...