
初二平面几何经典难题,已知AC=BD,求∠B的度数。
初二平面几何经典难题,已知ac=bd,求∠b的度数。 , 视频播放量 43771、弹幕量 97、点赞数 549、投硬币枚数 63、收藏人数 473、转发人数 368, 视频作者 毛老师数学课, 作者简介 一起 …
Prove that if a|b, c|d, then ac|bd - Mathematics Stack Exchange
It follows that $$ bd = (k_1a)(k_2c) = (k_1k_2)(ac) $$ Let $k$ be equal to the integer $k_1 k_2$. We see that $(bd) = k(ac)$. Thus, $bd$ is divisible by $ac$.
如图,四边形ABCD中,AC,BD是对角线,三角形ABC为等边三角形,角ADC=30度,AD=3,BD…
2013年6月11日 · 分析:首先以CD为边作等边 CDE,连接AE,利用全等三角形的判定得出 BCD≌ ACE,进而求出DE的长即可.. 解答: 提示:此题主要考查了等边三角形的性质以及全等三 …
如图所示,在三角形ABC中,AB=AC,点D在AC上且BD=BC=AD, …
如图所示,在三角形abc中,ab=ac,点d在ac上且bd=bc=ad,求三角形各角的度数解:解法一:设∠a=x.∵ad=bd,∴∠abd=∠a=x;∵bd=bc,∴∠bcd=∠bdc=2x;∵ab=ac,∴∠abc=∠bcd=2x,∴∠dbc=x;∵x+2x+2x=180°,∴x
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如图,AC,BD相交于点O,且AB=DC,AC=DB.求证:∠ABO=∠D…
如图,AC,BD相交于点O,且AB=DC,AC=DB.求证:∠ABO=∠DCO.. 证明:连接BC.. ∴ AOB≌ DOC(AAS).. 连接BC,先证明 ABC≌ DCB,然后证明 AOB≌ DOC,即可证得.. …
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