
Al3+ is a symbol for aluminum? - Socratic
2018年3月28日 · The symbol for aluminium is #Al#, and can be found on the periodic table. See here: See here: For #Al^(3+)# , that's showing its cation, since aluminium tends to be stable in its #+3# oxidation state as an ion.
What is the electron configuration for #"Al"^(3+)#? - Socratic
2016年8月4日 · "Al"^(3+): 1s^2 2s^2 2p^6 Your starting point here will be the electron configuration of a neutral aluminium atom, "Al". Aluminium is located in period 3, group 13, and has an atomic number equal to 13. This tells you that the electron configuration of a neutral aluminium atom must account for a total of 13 electrons. The electron configuration of the neutral atom looks like this "Al: " 1s^2 ...
What is the number of electrons in an Al^(3+) ion? - Socratic
2016年1月25日 · The atomic number, Z, of aluminum metal is 13. What is 13-3? Clearly, there are 10 electrons associated with a single Al^(3+) ion. We don't need any chemistry to make this determination. The atomic number specifies the number of positively charged particles in the atomic nucleus. The aluminum nucleus contains 13 protons, 13 fundamental, positively charged particles; this is what identifies the ...
Calculate the molar mass of Al(C2H3O2)3 - Socratic
2018年3月6日 · 236 \\ "g/mol" To calculate the molar masses of Al(C_2H_3O_2)_3, we must take all the molar mass of the elements present. We have C_2,H_3,O_2 three times, and one Al atom. C_2 has the molar mass of two carbon atoms, that is 12*2=24 \\ "g/mol". H_3 has a molar mass of three hydrogen atoms, that is 1*3=3 \\ "g/mol". O_2 is oxygen gas, and has the mass of two oxygen atoms, and that'll be 16*2=32 ...
What is the atomic structure of Al +3? - Socratic
2018年3月11日 · Neutrons: 14 Protons: 13 Electrons: 10 Typically in any standard atom, we have the same number of electrons as protons. But we have a 3+ ion here. Therefore we have 3 less electrons than we normally have. 13-3 = 10 Therefore there are 10 electrons present. The electronic configuration will be: 1s^2 , 2s^2, 2p^6 Remember the last 3 electrons are donated elsewhere to make that 3+ aluminium ion.
How many chloride ions would combine with an Al^(3+) ion to …
2016年7月2日 · Aluminum ions have a #3^(+)"# charge with the formula #"Al"^(3+)"#. An ionic compound must be neutral, which means the positive and negative charges must be equal. So we need three chloride ions to bond with one aluminum …
How can I write the formula for aluminum oxide? - Socratic
2014年7月3日 · The formula for aluminum oxide is Al_2O_3. The correct answer is Al_2O_3. Let us see how we got the answer; Look at the electronic arrangement of Al and O atoms. Al ( Z= 13) has 13 electrons with following electronic configuration. 1s^22s^22p^63s^23p^1 It loses three electron in its 3s and 3p subshell to achieve stability and forms ion Al^(3+). Al^(3+) = 1s^22s^22p^6 O ( Z=8) on the other hand ...
HNO3(aq) --> Al(NO3)3(aq) + H2(g)? - Socratic
2015年11月10日 · 2Al + 6HNO_3 -> 2Al(NO_3)_3 + 3H_2 Most students are reluctant to double the beginning compound/element. Don't be afraid to. A helpful tool is to write out each element and count up how many of them are on each side. Then edit those amounts each time WITHOUT doubling back on yourself. If you just changed the number to match the other side, leave it and change something else first.
What is the name of Al(OH)_3? - Socratic
2015年12月16日 · The name of "Al(OH)"_3" is aluminum hydroxide. Ionic compounds are named for the elements or polyatomic ions of which they are made. We can know this is an ionic compound because it contains a metal ion and a polyatomic ion. The metal ion is "Al"^(3+)" and the polyatomic ion is "OH"^-", called the hydroxide ion.
What is the ionic compound formed between oxygen and …
2016年9月29日 · You speak of "alumina, "Al_2O_3. Aluminum generally forms Al^(3+) ions. Oxygen generally forms O^(2-) ions. So when the metal and the non-metal make music together they form a neutral compound, i.e. Al_2O_3 (i.e. 2xx3-3xx2=0). The ionic bonding is so strong (due to charge magnitude) in this material that it is reasonably insoluble.