2013年9月21日 · Use %Y insetead of %y. the latter matches only 2 digits %y Year without century as a zero-padded decimal number. 00, 01, ..., 99 %Y Year with century as a decimal number. 1970, 1988, 2001, 2013 Documentation here. Demo:

2019年3月21日 · I'm working with a data frame containing dates in the '%B - %Y' format and need to convert them back to a ...

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2018年2月28日 · A POSIXct date needs the day of the month to be complete and valid. You can add it to the date strings, then use the format "%B %Y %d" e.g. :

2021年8月20日 · If you know which languages to expect in advance, another option would be to set the appropriate locale. Side note, the names of the locales (i.e. the string to use for setting a specific one) depend on the operating system.

Additionally, %b signifies abbreviated month name (just the first 3 letters), while %B signifies the full month name. That's probably what you're looking for. – Prateek Dewan

arange generates lists (well, numpy arrays); type help(np.arange) for the details. You don't need to call it on existing lists.

2014年7月6日 · import datetime from datetime import timedelta s = "1 July 2013" d = datetime.datetime.strptime(s, "%e %B %Y") print d.strftime("%e %B %Y") However, I'm getting the following error: ValueError: 'e' is a bad directive in format '%e %B %Y' What's wrong with the formatting ? I'm using Python 2.7, if that helps.

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1 The underlying numpy array of pandas' datetime64[ns] column may be accessed in a particular dtype such as datetime64[Y] using the .to_numpy() method. Once converted into a numpy array, it may be viewed as number of years since UNIX Epoch using .view('int64') , so adding 1970 to the result produces the correct year.