CH3I + Na = CH3 + NaI is a Double Displacement (Metathesis) reaction where one mole of Methyl Iodide [CH 3 I] and one mole of Sodium [Na] react to form one mole of Methyl [CH 3] and one mole of Sodium Iodide [NaI]

CH3I + Na = C2H6 + NaI is a Double Displacement (Metathesis) reaction where two moles of Methyl Iodide [CH 3 I] and two moles of Sodium [Na] react to form one mole of Ethane [C 2 H 6] and two moles of Sodium Iodide [NaI]

2010年8月3日 · CH3I，是1°卤代烃，其最重要的反应就是SN2亲核取代反应。 I-是一个很好的离去基团，因此CH3I可以和各种亲核试剂反应。 即亲核试剂Nu-进攻C原子与I原子离去同时发生，中间经历一个过度态。 CH3I的有关性质，越详细越好CH3I，是1°卤代烃，其最重要的反应就是SN2亲核取代反应。 I-是一个很好的离去基团，因此CH3I可以和各种亲核试剂反应。 CH3I + AgNO3 → (Δ，C2H5OH) CH3ONO2 + AgI↓CH3I + NaCN → CH3CN.

单位：摩尔质量 - g / mol，质量 - g。 让我们使用检验方法来平衡这个方程。 对于每个元素，我们检查方程两边的原子数量是否平衡。 Na 已平衡: 试剂中有 1 个原子，产品中有 1 个原子。 O 已平衡: 试剂中有 1 个原子，产品中有 1 个原子。 C 已平衡: 试剂中有 1 个原子，产品中有 1 个原子。 I 已平衡: 试剂中有 1 个原子，产品中有 1 个原子。 H 已平衡: 试剂中有 4 个原子，产物中有 4 个原子。 让我们用代数方法平衡这个方程。 首先，我们将所有系数设置为变量 a, b, c, d, ... 把这 …

Na is balanced: 1 atom in reagents and 1 atom in products. O is balanced: 1 atom in reagents and 1 atom in products. H is balanced: 4 atoms in reagents and 4 atoms in products. Let's balance this equation using the algebraic method. First, we set all coefficients to variables a, b, c, d, ...

CH3I + NaOH = NaI + CH3OH is a Double Displacement (Metathesis) reaction where one mole of Methyl Iodide [CH 3 I] and one mole of Sodium Hydroxide [NaOH] react to form one mole of Sodium Iodide [NaI] and one mole of Methanol [CH 3 OH]

2 CH3I + 2 Na → C2H6 + 2 NaI - Balanced equation | Chemical Equations online! This is an oxidation-reduction (redox) reaction: CH3I is an oxidizing agent, Na is a reducing agent.

Na is balanced: 1 atom in reagents and 1 atom in products. H is not balanced: 5 atoms in reagents and 4 atoms in products. In order to balance H on both sides we:

CH3I + CH3ONa = CH3OCH3 + NaI is a Double Displacement (Metathesis) reaction where one mole of Methyl Iodide [CH 3 I] and one mole of Sodium Methoxide [CH 3 ONa] react to form one mole of Ethanol [CH 3 OCH 3] and one mole of Sodium Iodide [NaI]

Our expert help has broken down your problem into an easy-to-learn solution you can count on. Show the mechanism, step-by-step, arrows, correct product and stereochemistry. There’s just one step to solve this. The given reaction involve the conversion of primary amine to quaternary ammonium salt followed by t... Not the question you’re looking for?