2020年9月21日 · Write $\cos (5x)$ as a function of $\cos (x)$, answer with a polynomial. $$e^ {i\cdot5x} = \cos (5x) + i\sin (5x)$$ $$\cos (5x) + i\sin (5x) = (\cos (x) + i\sin (x))^5$$ and using the binomial theorem I th...

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∫cos x^5dx=∫cos x^4dsin x =∫（1-sin² x ）²dsinx =∫（1-2sin² x+sin x^4）dsin x =sin x -2/3sin x^3 +1/5 sin x^5 + c. 证明： 如果f(x)在区间I上有原函数，即有一个函数F(x)使对任意x∈I，都有F'(x)=f(x)，那么对任何常数显然也有[F(x)+C]'=f(x).即对任何常数C，函数F(x)+C也是f(x)的原函数。

Use the form acos(bx−c)+ d a cos (b x - c) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. Find the amplitude |a| | a |. Find the period of cos(5x) cos (5 x). Tap for more steps... Find the phase shift using the formula c b c b. Tap for more steps... List the properties of the trigonometric function.

2023年12月4日 · 为什么将cos(5x)化简成cosx， cosnx？利用积化和差公式化简成三角函数和的形式，是为了避免用到(uv)'=u'v+uv'，只需两次用到cosx的n阶导数公式，大大简化求导的过程。y=cos(5x)cos(6x) =½cos(11x)

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\int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx \sum_{n=0}^{\infty}\frac{3}{2^n} Show More

Take the inverse cosine of both sides of the equation to extract x x from inside the cosine. 5x = arccos(0) 5 x = arccos (0) Simplify the right side. Tap for more steps... Divide each term in 5x = π 2 5 x = π 2 by 5 5 and simplify. Tap for more steps... The cosine function is positive in the first and fourth quadrants.

5x + sinx + C Explanation: Split into two integrals; \displaystyle\int_ {_} {5} {\left. {d} {x}\right.} + \displaystyle\int_ {_} {\cos { {\left ( {x}\right)}}} {\left. {d} {x}\right.} Solve seperately; ... It is the amplitude, it will make the upper & lower bounds of the function on the y-axis higher and lower.

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