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How do you use the second fundamental theorem of Calculus to find the derivative of given ∫ (cos(t3)) from [cosx,7x] ...

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Take the inverse cosine of both sides of the equation to extract x x from inside the cosine. 7x = arccos(0) 7 x = arccos (0) Simplify the right side. Tap for more steps... Divide each term in 7x …

Use the form acos(bx−c)+ d a cos (b x - c) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. Find the amplitude |a| | a |. Find the period of cos(7x) cos …

多項式的導數是其各項導數的總和。 常數項的導數為 0。 ax^ {n} 的導數為 nax^ {n-1}。 -7\sin (7x^ {1})

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例题 x^ {2}-x-6=0 -x+3\gt 2x+1 直线\: (1,\:2),\: (3,\:1) f (x)=x^3 证明\:\tan^2 (x)-\sin^2 (x)=\tan^2 (x)\sin^2 (x) \frac {d} {dx} (\frac {3x+9} {2-x}) (\sin^2 (\theta))' \sin (120) \lim _ {x\to 0} (x\ln (x)) …

Use the Sum to Product identity: cos(s)+cos(t) =2cos(2s+t)cos(2s −t) = 2cos(23x+7x)cos(23x−7x)