
Find the area of the region that lies inside the first curve ... - Wyzant
2016年10月21日 · A = 1/2 ∫80 cos 2 θ - 8cosθ -16 dθ A = ∫ 40 cos 2 θ - ∫4cosθ - ∫8 dθ 0 to 30 I hope that you can do the rest because i"m tired of typing math.
Find the area of the region that lies inside the first curve ... - Wyzant
2020年12月2日 · 1/2 · ∫ [ -7 + 14 cos(θ) ] dθ; evaluated from - π/3 to π / 3 The limits of integration are∫ from - π / 3 to π / 3, and the graph is symmetrical; therefore, one may obtain the same result by integrating from 0 to π /3 and multiplying the above integral by 2 obtaining:
Find the area of the region that lies inside the first curve and ...
2020年3月31日 · cos θ = 1/2 so θ = ± π/3. In polar coordinates, area is ∫1/2 r 2. so here we want the larger area: 1/2 ∫(9cosθ) 2 dθ. and the smaller area: 1/2 ∫(4+cosθ) 2 dθ (both are from -π/3 to π/3) Then the area is the big area minus the small area. If we're solving these integrals without a calculator we will need the trig identity cos 2 ...
Identify the curve by finding a Cartesian equation for the curve, r ...
Q: Obtain the parametric equations of: An epicycloid curve described by a point on the circumference of… A: Q: The intercepts on the horizontal axis are (pi/6 ,0) and (5pi/6, 0). graph the corresponding polar…
Use implicit differentiation to find an equation of the tangent line …
Paula G. asked • 10/01/15 Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y sin 8x = x cos 2y, (p/2, p/4)
Use implicit differentiation to find an equation of the ... - Wyzant
Mia L. asked • 10/15/15 Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
Find the area of the region that lies inside the first curve ... - Wyzant
2022年6月24日 · One way to do this is to draw the curves and see that the areal region can be described as the differences in the "wedge-shapes" of r 1 and the portion of the wedge shape in r 2 for the range of theta that is of interest.
Answered: Consider the following curve. x = sin(6t), y = -cos(6t), z ...
Consider the following curve. x = sin(6t), y = -cos(6t), z = 24t Using the given parametric equations, give the corresponding vector equation r(t). r(t) = (sin (6t), - cos (6t),241) Find r'(t) and Ir'(t)\. r'(t) = |r'(t) = √612 (6 cos (61),6 sin (6t),24) Find the equation of the normal plane of the given curve at the point (0, 1, 4x). -6x+12z-48=0 x Now consider the osculating plane of the ...
Find the area of the region that is inside the curve r = sin ... - Wyzant
2021年3月4日 · Find the area of the region that is inside the curve r = sin θ and outside the curve r = 1 + cos θ. Your work must include the integral, but you may use your calculator to find the area to 3 decimal places.
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2021年4月4日 · The figure above shows the graph of the polar curve r=1−2cosθ for 0≤θ≤π and the unit circle r=1. (a) Find the area of the shaded region in the figure. Question 2 (b) Find the slope of the line tangent to the polar curve r=1−2cosθ at the point where x=−2. Show the computations that lead to your answer. Question 3