The basic trigonometric identities are: Cosec θ = 1/Sin θ Sec θ = 1/Cos θ Cot θ = 1/Tan θ Tan θ = Sin θ/Cos θ Cot θ = Cos θ/Sin θ Sin2θ + Cos2 θ = 1 1 + tan 2 θ = sec 2 θ

它们之间的关系是csc(x) = 1/sin(x)，sec(x) = 1/cos(x)。 这些关系在解决三角函数问题、进行角度转化和简化计算时很有用。 通过例题讲解，我们演示了如何利用已知的sin(x)的值来求取csc(x)的值，加深对csc和sec与sin、cos、tan之间关系的理解和应用。

(ac) 2 + (bc) 2 = 1. a/c is Opposite / Hypotenuse, which is sin(θ) b/c is Adjacent / Hypotenuse, which is cos(θ) So (a/c) 2 + (b/c) 2 = 1 can also be written:

Secant, cosecant and cotangent, almost always written as sec, cosec and cot are trigonometric functions like sin, cos and tan. sec x = 1 cos x. cosec x = 1 sin x cot x = 1 = cos x tan x sin x. Note, sec x is not the same as cos-1 x (sometimes written as arccos x).

sec、csc、cot的三角函数公式是secx=1/(cosx)、cscx=1/(sinx)、cotx=1/(tanx)=(cosx)/(sinx)。 三角函数是基本初等函数之一，是以角度为自变量，角度对应任意角终边与单位圆交点坐标或其比值为因变量的函数。

In Trigonometry, different types of problems can be solved using trigonometry formulas. These problems may include trigonometric ratios (sin, cos, tan, sec, cosec and cot), Pythagorean identities, product identities, etc. Some formulas including the sign of ratios in different quadrants, involving co-function identities (shifting angles), sum ...

sin θ = 1/ cosec θ or sin θ x cosec θ = 1 cos θ = 1/ sec θ or cos θ x sec θ = 1; tan θ = 1/cot θ or tan θ x cot θ = 1; Quotient Relations. Again, as the name suggests, quotient relations involve three trigonometric ratios; where one is the quotient obtained after division operation between the other two. For example, tan θ = sin θ ...

2017年5月29日 · The cosecant (), secant and cotangent functions are 'convenience' functions, just the reciprocals of (that is 1 divided by) the sine, cosine and tangent. So So csc ⁡ ( x ) = 1 sin ⁡ ( x ) {\displaystyle \csc(x)={\frac {1}{\sin(x)}}}

单位圆可以被认为是通过改变邻边和对边的长度并保持斜边等于1查看无限数目的三角形的一种方式。 对于大于2π或小于−2π的角度，简单的继续绕 单位圆 旋转。

2024年12月16日 · Ex 2.1, 3 Find the principal value of cosec−1 (2) Let y = cosec−1 2 cosec y = 2 cosec y = cosec (𝝅/𝟔) ∴ y = 𝝅/𝟔 Since Range of cosec-1 is [−π/2,π/2] – {0} Hence, Principal Value is 𝝅/𝟔. Show More