Take the inverse cosine of both sides of the equation to extract x x from inside the cosine. Simplify the right side. Tap for more steps... The cosine function is positive in the first and fourth …

Take the inverse cosine of both sides of the equation to extract x x from inside the cosine. Simplify the right side. Tap for more steps... The cosine function is positive in the first and fourth …

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\sin^{2}{\frac{\theta}{2}} = \frac{1 - \cos{\theta}}{2} \\ \sin{\frac{\theta}{2}} = \pm \sqrt{\frac{1 - \cos{\theta}}{2}} \\ \cos^{2}{\frac{\theta}{2}} = \frac{1 + \cos{\theta}}{2} \\ \cos{\frac{\theta}{2}} = …

\sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim …

What is the general solution for cos (x)= (sqrt (3))/2 ?

a\sin {x} + b\cos {x} = \sqrt {a^2+b^2} \sin {\left (x + \arctan\frac {b} {a}\right)}. 作用：将形如 的函数转换为形如 的函数。 这一转换并不改变三角函数的角频率。 将正弦、余弦、正切函数都转化 …

sinx+cosx=\sqrt {2}sin (x+\frac {\pi} {4}) sinx-cosx=\sqrt {2}sin (x-\frac {\pi} {4}) 奇变偶不变，符号看象限。 tg就是tanx，ctg就是cotx，不要慌张. 表格是最全的，但是记忆量比较大，记住如下 …

若 x\in\left[0,\frac{\pi}{2}\right] ，则 \cos x\in(0,1) ， \sin x\in(0,1) ， 令 \cos x = t,\sin x=\sqrt{1 - t^{2}} ，则 t\in(0,1) ， \sqrt{1 - t^{2}}\in(0,1) 。 ∵ y = \sin t,y=\cos\sqrt{1 - t^{2}} 在 t\in(0,1) 上均 …

2018年5月4日 · #cos x = cos a# has solutions #x= \pm a + 360^circ k quad # for integer #k#. #cos x = -1/sqrt{2} = cos( 120^circ) # # x = \pm 120^circ + 360^circ k #