
What is the acidic basic or neutral character for crbr3?
2024年6月2日 · CrBr3 is the chemical formula for chromium(III) bromide, a compound composed of the elements chromium and bromine. It is used in various chemical applications and can act as a catalyst in certain ...
What is the name of CrBr3? - Answers
2024年5月22日 · Chromium bromide. Updated: 5/22/2024 Wiki User. ∙ 16y ago
What is the name for the ionic compound CrBr3? - Answers
2024年5月31日 · The name for the ionic compound CrBr3 is chromium(III) bromide.
What is CrBr3? - Answers
CrBr3 is the chemical formula for chromium(III) bromide, a compound composed of the elements chromium and bromine. It is used in various chemical applications and can act as a catalyst in certain ...
What is the formula for chromium III bromide hexahydrate
2024年6月14日 · CrBr3 is the chemical formula for chromium(III) bromide, a compound composed of the elements chromium and bromine. It is used in various chemical applications and can act as a catalyst in certain ...
What is the formula for chromium 2 bromide? - Answers
2024年6月1日 · CrBr3 is the chemical formula for chromium(III) bromide, a compound composed of the elements chromium and bromine. It is used in various chemical applications and can act as a catalyst in certain ...
Chromium III and bromine make - Answers
2024年5月22日 · CrBr3 is the chemical formula for chromium(III) bromide, a compound composed of the elements chromium and bromine. It is used in various chemical applications and can act as a catalyst in certain ...
What is the solution CrBr3? - Answers
Chromium (III) Bromide. Wiki User. ∙ 14y ago. This answer is:
Is Br2 an ionic or covalent? - Answers
2024年5月23日 · Is Br2 ionic polar covalent or covalent? Br2 is a covalent molecule. It consists of two bromine atoms that share a pair of electrons to form a nonpolar covalent bond.
What is the chemical formula for chromium II borate? - Answers
2024年5月31日 · The formula is CrBr2. This is derived by balancing the electrons from the atoms. Chromium II has a charge of +2 and Bromine has a charge of -1. Therefore in order for this molecule to be ...