2014年12月18日 · The derivative of cos^3(x) is equal to: -3cos^2(x)*sin(x) You can get this result using the Chain Rule which is a formula for computing the derivative of the composition of two …

2015年9月15日 · Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer

2017年2月7日 · d/dxcos^(-1)(x) = -1/sqrt(1 -x^2) When tackling the derivative of inverse trig functions. I prefer to rearrange and use Implicit differentiation as I always get the inverse …

2017年1月16日 · All you need to do is cancel the I_ns and move the -nI_n to the left hand side: n int cos^n x dx=sin x cos^(n-1)x + (n-1) int cos^(n-2)x dx . Dividing through by n gives the …

Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer

2014年7月31日 · The answer is: #dy/dx = -1/(sqrt(1-x^2))# This identity can be proven easily by applying #cos# to both sides of the original equation:

2014年10月16日 · Recall: int{g'(x)}/{g(x)}dx=ln|g(x)|+C (You can verify this by substitution u=g(x).) Now, let us look at the posted antiderivative. By the trig identity tan x={sin x}/{cos x}, int tan x …

2018年4月26日 · The last step came from the identity #sin^2(theta)+cos^2(theta)=1#, which is restated as #sin(theta)=sqrt(1-cos^2(theta))#. We should also remember that #cos(f(x))=x# , …

2015年10月22日 · See the explanation. Before learning the chain rule, you need to use a fact from trigonometry: cos(-x) = cosx Therefore, d/dx(cos(-x) = d/dx(cosx) = -sinx (By the way sin( …

2014年9月8日 · Answer 2sin(x)cos(x) Explanation You would use the chain rule to solve this. To do that, you'll have to determine what the "outer" function is and what the "inner" function …