Assume f(0)=f'(0)=0, prove there exists a positive constant such …
Dec 9, 2011 · Assume that f is a differentiable function such that f(0)=f'(0)=0 and f''(0)>0. Argue that there exists a positive constant a>0 such that f(x)>0 for all x in the interval (0,a). Can …
Intuitively understanding div(curl F) = 0 - Physics Forums
Apr 4, 2012 · If you know about exterior derivatives, then this identity is equivalent to [itex]d^2 = 0[/itex]. To give a "physical picture" for this identity, first use Gauss's Theorem for …
If integral f =0, prove that f(x)=0 for all x in [a,b] - Physics Forums
Feb 3, 2009 · If f(x_0)=c and c > 0 then the function must go up to atleast c, and since it is continuous it does not "jump" there. I was thinking of making a small partition of a,x_0, and b. I …
What frequency will the bat hear? - Physics Forums
Dec 15, 2024 · ##F_a=\frac 12(f_0\frac{c+v}{c-v}-f_0)=f_0\frac{v}{c-v}## in agreement with the official answer. The ‘beat frequency’ is in fact ##2F_a## corresponding to your answer. That’s …
##f(2x)=f^2(x)-2f(x)-1/2## then find ##f(3)## - Physics Forums
Mar 4, 2025 · My solution: Let ##f(x+y)=f(x)f(y)-[f(x)+f(y)]-1/2## İf ##y=x## we find functional equation that given us. So for ##x=y=1## then ##f(2)=-1/2## İf we evaluate ##x=1, y=2## at …
Understanding the graphical effect of f(x+a) - Physics Forums
Feb 22, 2025 · In your parabola example, if p > 0 and q > 0, the graph of ##f(x) = a(x + p)^2 + q## will be translations to the left by p and up by p of the graph of ##y = ax^2## Yes - it's intended …
SOLUTION: Given f (x) = x2 + 3x 5, find f (0). -5 Did I do this right ...
SOLUTION: Given f(x) = x2 + 3x – 5, find f(0). -5 Did I do this right. Can you show me the steps
Rolling without slipping problem - Physics Forums
Mar 6, 2025 · ##M a_{cm} = F_{ext}## Hi, I started this thread to address the solution of this problem. ProblemView attachment 358160 A yo-yo of radii ##R_1=R## and …
If f(x-y). f(y)=f(x), f(5)=32, then what is f(7)? - Physics Forums
Jan 21, 2025 · From ##f(0)f(x) = f(x)## and with ##f(0)=0##, one can deduce that ##f(x) \equiv 0\, \forall\, x##. You can however rule that other solution out due to the fact that ##f(5) = 32##. …
SOLUTION: How do you solve questions like f(0)=2, f(2)=4 and …
That's the same problem as Find the equation of the line that passes through the two points (0,2) and (2,4) except that when you finish you write f(x) instead of y. Use the slope formula: Use …