2022年1月28日 · To assemble the global $K$ and $F$, it suffices to add up each contribution of $K_e$ and $F_e$ by a node in an element. Pseudo algorithm: -for node in the globalnodelist

推导固体力学有限元基本方程（ku=f，其中k为整体刚度矩阵，u为整体节点位移列阵，f为整体节点外载荷列阵）的方法主要有三类：

应该说结构刚度矩阵在没有引入边界条件之前是奇异的，因为如果没有引入边界条件的话，对整个结构来说存在着刚体位移，也就是说ku=f这个方程存在着非零解，引入边界条件的话就是约束 …

Finite elements and finite differences produce large linear systems KU = F. The matrices K are extremely sparse. They have only a small number of nonzero entries in a typical row. In …

2022年10月13日 · When you step up to a weighing scales, the floor receives a force F=mg, but it does not move, hopefully for you. Such a force is called in mechanics "passive force" or …

列写运动方程时要选定一个正方向，计算各力在正方向的投影。 加速度的正负号是由合外力的正负决定的，因此在列写方程时只要 用. x 或 y 或 z 表示就可以了。 2. 用牛顿第二定律列写运动微 …

What are the nodal displacements for a given structure (= stiffness matrix K ) due to a given load (= load vector F ) ? 1. Element nodal displacements. 2. Element end forces. 3. Element stress …

F=KU可以推出K\F=U,当没有约束时,给个力F的话,物体就一直运动,位移U就无穷大了,所以K应当是奇异的,不可求逆,是不是就是说K的行列式为零? 但是我现在遇到的问题是,我求一个等参单元, …

2018年6月20日 · Inertial forces result from Newton's second law (F = MA). So in a dynamic analysis, we need to account for the accelerations. Where MA is the inertial component and …

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