From the balanced equation, 1 mol of Fe2O3 produces 1 mol of Al2O3. 0.2685 mol Fe2O3 will produce 0.2685 mol of Al2O3. Molar mass of Al2O3 = 101.96 g/mol; Max mass of Al2O3 = 0.2685 mol × 101.96 g/mol = 27.38 g; Therefore, the maximum mass of aluminum oxide that could be produced is 27.38 g. Learn more about Thermite Reaction Stoichiometry here:

Given: Fe2O3 + 3C → 2Fe + 3COFor this reaction, we have to balance the equation: Fe2O3 + 3C → 2Fe + 3COThe ratio of carbon and carbon monoxide is 3:3 = 1:1. The molecular weight of carbon = 12.01 g/mol1 mol of C produces 1 mol of CO36g of C is equal to 36/12.01= 2.9983 mol CO2.9983 mol of CO is produced

Calculate the enthalpy change for the thermite reaction: 2Al(s)+Fe2O3(s)→2Fe(s)+Al2O3(s), ΔH∘rxn=−850 kJ when 12.0 mol of Al undergoes the reaction with a stoichiometrically equivalent amount of Fe2O3. Express your answer to three significant …

Final answer: To find out how many grams of Iron (III) oxide (Fe2O3) can be produced from 25.0 g of iron, we calculate the number of moles of iron, use the stoichiometric ratio from the balanced equation, and then convert the moles of Fe2O3 to grams to get the final yield of 35.68 g of Fe2O3.

2 Fe(OH)3 → Fe2O3 + 3H₂O 100 p If you have 7.2 moles of Iron(III) Hydroxide how many moles of water will be produced? Community Answer Determine the mass of Iron (III) oxide (Fe2O3) produced in the decomposition reaction of 100.0 grams of Iron (III) hydroxide (Fe(OH)3).

2023年10月11日 · In the chemical equation Fe2O3(s) + 3C(s) → 2Fe(s) + 3CO(g), it shows that Fe2O3 reacts with C in a 1:3 ratio. Therefore, to calculate the amount of carbon needed to react with 30.8g of Fe2O3, we first need to find out the molar mass of Fe2O3 which is approximately 159.7g/mol. Dividing 30.8g by this, we will get the number of moles of Fe2O3 ...

2 Al (s) + Fe2O3 (s) → 2 Fe (s) + Al2O3 (s) As the statement says that aluminun is in excess, the limiting reactant is the Fe2O3. Second step: Find out the moles in the reactant. Molar weight Fe2O3: 159.7 g/m. Mass / Molar weight = moles. 50 g /159.7 g/m = 0.313 moles. Third step: Analyse the reaction. 1 mol of Fe2O3 makes 2 moles of Fe.

The correct balanced equation for the reaction of rust, Fe2O3, with hydrochloric acid, HCl, is Fe2O3 + 6 HCl → 2 FeCl3 + 3 H2O. Rust, also known as iron(III) oxide, reacts with six molecules of hydrochloric acid to produce two molecules of iron(III) chloride and three molecules of water.

2021年2月25日 · That is the Fe2O3 mole ratio: Because Fe is a** 1:2** element, the mole of Fe is 2x2=4 moles. Because the mole ratio of Fe2CO3 to CO2 is 1:3, the moles of Co2 are 2 x 3 = **6 moles. ** Thus, If 2 moles of Fe2O3 react with 9 moles of CO, moles of each product is formed will be** 6 moles.** For more details regarding moles, visit: brainly.com ...

2020年3月12日 · Fe2O3 + C → Fe + CO2. Step 2: Balancing the equation. Fe2O3 + C → Fe + CO2. On the left side we have 3x O (in Fe2O3), on the right side we have 2x O (in CO2). To balance the amount of O on both sides, we have to multiply Fe2O3, on the left side, by 2 and CO2 , on the right side, by 3. 2Fe2O3 + C → Fe + 3CO2