2018年9月18日 · Given f(x) = 3x + 2 and g(x) = -2x2+4 Find f(g(2)) What would you do in order to solve? Explain in words the process to solving f(g(2)).

2020年4月30日 · Therefore, (g o f)(2) = 15. As a side note, there is a second way to solve these kind of problems. Take the entire function f , and plug it into the function g, then plug the number 2 in. Using the example from before: g(x) = 2x + 1. f(x) = 4x - 1 (g o f)(x) = 2(4x-1) + 1 which simplifies to (g o f)(x) = 8x - 1. Now plug in the 2: (g o f)(2 ...

For example, if we have two functions f(x) and g(x) that are written as f(x) = x^4/8 g(x) = (8+x)/5 then when x=2, f(x) = (2^4)/8 = 16/8 = 2 = f(2), and g(x) = (8+2)/5 = 2 = g(2). Since both functions equal the same number when their inputs equal 2 (x=2), then the values of both functions are equal when their inputs equal 2. This can be written ...

2023年3月6日 · A) (f + g)(x) = f(x) + g(x) = x + 5x = 6x. B) The domain of (f + g)(x) is all real numbers, since there are no restrictions on the domain of x. C) (f − g)(x) = f(x) − g(x) = x − 5x = −4x. D) The domain of (f − g)(x) is all real numbers, since there are no restrictions on the domain of x. E) (fg)(x) = f(x)g(x) = x(5x) = 5x^2

2020年3月16日 · Suppose that f(2) = −4, g(2) = 3, f '(2) = −5, and g'(2) = 1. Find h'(2). (a) h(x) = 4f(x) − 5g(x)

2019年6月13日 · If F(x) = f (g (x) ), then by the Chain Rule. F ' (x) = f ' (g(x)) g ' (x) Now is simply a matter of plugging in numbers.

2022年11月26日 · g(x)= −5+3 x 2. f(x)= 7-6 x (a) Find (g/f)(−2) (g/f)(x)= (-5+3x 2)/(7-6x) (g/f)(-2)= (-5 + (-2) 2)/(7-6(-2)) = (-5+4)/(7+12) = 1/19. (b) Find all values that are NOT in the domain of g/f. To avoid division by zero, 7 - 6x can't equal zero. So, 7 - 6x ≠ 0, then 7 ≠ 6x, then 7/6 ≠ x. So the domain of x all real numbers except 7/6. Enjoy

2017年9月18日 · Retired math prof. Calc 1, 2 and AP Calculus tutoring experience. About this tutor › Since f and g are even functions, the graphs of f and g are symmetric with respect to the y-axis.

f(2) = 2^2 = 4. when you say f(g(x)), then the independent variable in the equation becomes g(x). g(x), however, was the dependent variable in another equation, so it's value had to be calculated before you could put it into f(g(x)). that's exactly what we did above. we solved for g(2) to get 7. then we solved for f(g(x)) to get f(7) = 3.

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