2018年9月18日 · Given f(x) = 3x + 2 and g(x) = -2x2+4 Find f(g(2)) What would you do in order to solve? Explain in words the process to solving f(g(2)).

2020年4月30日 · Therefore, (g o f)(2) = 15. As a side note, there is a second way to solve these kind of problems. Take the entire function f , and plug it into the function g, then plug the …

For example, if we have two functions f(x) and g(x) that are written as f(x) = x^4/8 g(x) = (8+x)/5 then when x=2, f(x) = (2^4)/8 = 16/8 = 2 = f(2), and g(x) = (8+2)/5 = 2 = g(2). Since both …

2023年3月6日 · A) (f + g)(x) = f(x) + g(x) = x + 5x = 6x. B) The domain of (f + g)(x) is all real numbers, since there are no restrictions on the domain of x. C) (f − g)(x) = f(x) − g(x) = x − 5x …

2020年3月16日 · Suppose that f(2) = −4, g(2) = 3, f '(2) = −5, and g'(2) = 1. Find h'(2). (a) h(x) = 4f(x) − 5g(x)

2019年6月13日 · If F(x) = f (g (x) ), then by the Chain Rule. F ' (x) = f ' (g(x)) g ' (x) Now is simply a matter of plugging in numbers.

2022年11月26日 · g(x)= −5+3 x 2. f(x)= 7-6 x (a) Find (g/f)(−2) (g/f)(x)= (-5+3x 2)/(7-6x) (g/f)(-2)= (-5 + (-2) 2)/(7-6(-2)) = (-5+4)/(7+12) = 1/19. (b) Find all values that are NOT in the domain of …

2017年9月18日 · Retired math prof. Calc 1, 2 and AP Calculus tutoring experience. About this tutor › Since f and g are even functions, the graphs of f and g are symmetric with respect to the …

f(2) = 2^2 = 4. when you say f(g(x)), then the independent variable in the equation becomes g(x). g(x), however, was the dependent variable in another equation, so it's value had to be …

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