Phản ứng CuO + HNO 3 hay CuO ra Cu(NO 3) 2 thuộc loại phản ứng trao đổi đã được cân bằng chính xác và chi tiết nhất. Bên cạnh đó là một số bài tập có liên quan về CuO có lời giải, mời các bạn đón xem:

CuO+2HNO₃=Cu (NO₃)₂+H₂O稀硝酸与氧化铜反应，为金属氧化物与酸的反应，生成相.

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a CuO + b HNO3 = c Cu + d NO3 + f H2O. Create an equation for each element (Cu, O, H, N) where each term represents the number of atoms of the element in each reactant or product.

1 CuO(s) + 2 HNO 3 (aq) = 1 Cu(NO 3) 2 (aq) + 1 H 2 O(l) N is balanced: 2 atoms in reagents and 2 atoms in products. O is balanced: 7 atoms in reagents and 7 atoms in products.

cu+4hno3(浓）===cu(no3)2+2no2↑+2h2o 3cu+8hno3(稀)==3cu(no3)2 +2no↑+4h2o 金属和浓硝酸反应多生成no2,和稀硝酸反应多生成no. 和浓硝酸反应一段时间后硝酸变稀,所以会先生成no2,后生成no 好容易搞错的,哈哈,注意他们的不同

已求解并配平的化学方程式 cuo + 2 hno3 → cu(no3)2 + h2o 具有完整的产物. 请求补充完整产物并配平方程. 如果未启用JavaScript，某些功能可能无法正常运行。

To balance CuO + HNO3 = Cu (NO3)2 + H2O you'll need to be sure to count all of atoms on each side of the chemical equation. Once you know how many of each type of atom you can only change the...

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a Cu + b HNO3 = c CuO + d N2 + f H2O. Create an equation for each element (Cu, H, N, O) where each term represents the number of atoms of the element in each reactant or product.

2013年7月18日 · 3cu2o+14hno3==6cu(no3)2+2no+7h2o方法是这样的：看反应物和产物，cu2o中cu被氧化，这个物质升高2价，hno3中的n被还原成no，降低3价，所以cu2o前面的系数是3，还原产物no的系数是2.作为氧化还原反应，电荷配平就结束了，还有hno3是作为酸和碱性氧化物来反应 …

cu和hno3反应方程式配平Cu 由0价升为+2价,HNO3中的N由+5降为NO中的+2价； 2-0=2,5-2=3,2和3的最小公倍数为6； 那么Cu前写上3,NO前写上2（不在HNO3前写上2是因为有一部分的HNO3中的N没有改变化合价.即HNO3在这个反