Whitney D. asked • 05/16/18 A fair coin is tossed 5 times. What is the probability of getting at least three heads on consecutive tosses?

Let, H be the head and T be the tail, then total number of outcomes or Sample space will be n(S) = {HHHHH, HHHHT, HHHTH, HHTHH, HTHHH, THHHH} = 6 Number of favourable outcomes or n(E) = {HHHHT, HTHHH, HHTHH, HHHTH, HHHHT} = 5 (Here, you can see that we have 4 …

2019年12月3日 · Similarly, for P(H=4) we have all combinations with four heads and one tail, which gives us five combinations: THHHH, HTHHH, HHTHH, HHHTH, HHHHT. So P(H=4) = 5 / 32. Now we have P(H=2) and P(H=3) to calculate.

2021年10月8日 · HHHHT. HHHTH. HHTHH. HTHHH. THHHH. 5 ways to get exactly 4 head. HHHHH. 1 way to get exactly 5 heads. 5+10 ...

2018年6月17日 · Five men and three women applied for 2 scholarships. What is the probability that both the winners will be men

2015年5月1日 · The sample points would be all combinations of Heads or Tails for 5 coins, so there are 2 5 possible outcome for the set of heads and tails, { (HHHHH), (HHHHT)...(TTTTT)} For this question, X is the number of heads, which means there could be