KI + Cl2 = KCl + I2 is a Single Displacement (Substitution) reaction where two moles of aqueous Potassium Iodide [KI] and one mole of Dichlorine [Cl 2] gas react to form two moles of aqueous Potassium Chloride [KCl] and one mole of solid Diiodine [I 2]

1 Cl 2 + 1 KI = 1 I 2 + 1 KCl 对于每个元素，我们检查方程两边的原子数量是否平衡。 Cl 不平衡: 试剂中有 2 个原子，产物中有 1 个原子。 为了平衡双方的Cl，我们： 将 KCl 的系数乘以 2 1 Cl 2 + 1 KI = 1 I 2 + 2 KCl K 不平衡: 试剂中有 1 个原子，产物中有 2 个原子。 为了 ...

1 KI + 1 Cl 2 = 1 KCl + 1 I 2 For each element, we check if the number of atoms is balanced on both sides of the equation. K is balanced: 1 atom in reagents and 1 atom in products.

2016年12月1日 · 将Cl2通入KI溶液中有什么现象通入氯气少量有I2生成，溶于水中是黄色-棕黄色，2KI+Cl2=2KCl+I2继续通入氯气过量，溶液又恢复到无色KI+3Cl2+3H2O=KIO3+6HCl再通入氯气，就等于氯气溶于水，溶液呈浅黄绿色。

Cl + KI = KCl + I2 is a Single Displacement (Substitution) reaction where two moles of Chlorine [Cl] gas and two moles of aqueous Potassium Iodide [KI] react to form two moles of aqueous Potassium Chloride [KCl] and one mole of solid Diiodine [I 2]

碘化钾（ki）溶解时，离解为k+和i-离子。 根据化学反应原理，氯气中的氯原子会与碘离子结合，形成氯化物离子（Cl-），而碘化物离子（I-）则会与氯离子结合，生成碘分子（I2）。

Units: molar mass - g/mol, weight - g. Let's balance this equation using the inspection method. For each element, we check if the number of atoms is balanced on both sides of the equation. K is balanced: 1 atom in reagents and 1 atom in products. Cl is not balanced: 1 atom in reagents and 2 atoms in products.

卤素单质氧化性强弱的顺序：F2＞Cl2＞Br2＞I2。 但是，如果把氟气通入到氯化钠溶液中，并不能将氯化钠中的氯元素置换出来，而是优先和水反应，反应的化学方程式为：2F2＋2H2O＝4HF＋O2↑，这是氟气的特殊性，它是氧化性最强的非金属单质。 你明白了吗？ 欢迎点赞＋关注，交流讨论，祝你进步，迈进985！ 是KI+CI2+3H2O＝KIO3+6HCI还是2KI+CI2=2KCI+I2？ 两者又有什么区别？

1 KI + 1 Cl 2 = 1 KCl 2 + 1 I 对于每个元素，我们检查方程两边的原子数量是否平衡。 K 已平衡: 试剂中有 1 个原子，产品中有 1 个原子。

2 KI + Cl2 → 2 KCl + I2 - Balanced equation | Chemical Equations online! This is an oxidation-reduction (redox) reaction: KI is a reducing agent, Cl2 is an oxidizing agent. Appearance: Greenish-yellow compressed liquefied gas with pungent odour ; Greenish-yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.]