2015年2月12日 · Try to write it as a log: ln(x)=ln3 which is: x=e^(ln(3)) But to have: ln(x)=ln3 means that x=3 or: e^(ln(3))=3

2016年8月4日 · ln(e^3)=3 By definition, log_a(x) is the value such that a^(log_a(x)) = x From this, it should be clear that for any valid a and b, log_a(a^b)=b, as log_a(a^b) is the value such that …

e^ln 3-----ln 3 means the power of e that gives you 3-----You are raising e to that power so you get 3 as ...

2016年2月10日 · Given fuction is e^(3lnx) Now, we know the logarithmic identity logm^n=nlogm and m^(log_mn)=n So using the above identities, we can reduce the equation. …

2016年8月5日 · In our case if we raise e to the ln x, we are just left with x on the left side since #e^(x)# and ln undo each other: #cancele^(cancel"ln"x) = 3# Now, we have to do the same …

2015年12月3日 · ln(1/e^(3))=ln(e^(-3))=-3. Since ln(x) and e^{x} are inverse functions, ln(e^{x})=x for all values of x. Since 1/e^{3}=e^{-3} by definition of negative exponents, it ...

2016年2月6日 · #color(brown)("Total rewrite as changed my mind about pressentation.")# #color(blue)("Preamble:")# Consider the generic case of #" "log_10(a)=b#

2016年6月22日 · It is e^-(ln3)=1/(e^(ln3))=1/3

2018年4月19日 · x=3 Remember that: log_a(b^c)=clog_a(b) Therefore: =>log_e(e^x)=3 =>xlog_e(e)=3 =>x*1=3 =>x=3. A way to very quickly see the answer without much math at all …

For example, to approximate #ln(7)#, split the interval #[1, 7]# into a number of strips of equal width, and sum the areas of the trapezoids with vertices: