
SOLUTION: given that log7=0.8451and log6=0.7782 find log 25.2
Question 1091414: given that log7=0.8451and log6=0.7782 find log 25.2 Found 2 solutions by Alan3354, MathLover1:
SOLUTION: 2logx=log25; solve for x - Algebra Homework Help
You can put this solution on YOUR website! 2log (x)=log (25) First use the property of logarithms, , to move the 2 into the argument as an exponent: Now, since the logs of and 25 are equal, …
SOLUTION: Evaluate the expression log4 + log25
Click here to see ALL problems on logarithm Question 322631: Evaluate the expression log4 + log25 Answer by stanbon (75887) ( Show Source ):
SOLUTION: log (6*5^x-25*20^x)=x+log (25) - Algebra Homework …
Click here to see ALL problems on logarithm Question 397589: log (6*5^x-25*20^x)=x+log (25) Answer by lwsshak3 (11628) ( Show Source ):
SOLUTION: find value of log8 25 if log 2= 0.3010 - Algebra …
Question 437250: find value of log8 25 if log 2= 0.3010 Answer by stanbon (75887) (Show Source):
SOLUTION: Given log 2 = 0.3010, log 3 = 0.4771. Find the value of …
So we want to expression 12 and 5 as a product, quotient or power of number (s) whose logarithm you were given or whose logarithm you should know. log (12) One way to find this logarithm is …
SOLUTION: Evaluate the following expression: Log5 1/25
Click here to see ALL problems on logarithm Question 173435: Evaluate the following expression: Log5 1/25 Answer by solver91311 (24713) ( Show Source ):
SOLUTION: solve x logx 25 = -2 ***the x is subscript of log
You can put this solution on YOUR website! solve for x logx 25 = -2 Use the rule that says: A logarithmic equation of the form logBA = C is equivalent to and can be rewritten as the …
SOLUTION: log5 25=x - Algebra Homework Help
You can put this solution on YOUR website! log 5 25 = x is explained in exponential form.
SOLUTION: simplify: log 2+16 log (16/15)+12 log (25/24)+7 log …
In order to use this property the logs have to have coefficients of 1. So we will start by using another property of logarithms: to move the "bad" coefficients into the arguments as …