How would you balance Na(s) + Cl2 → NaCl(s)? - Socratic
2015年10月18日 · The balanced equation is "2Na(s)"+"Cl"_2("g")"rarr"2NaCl(s)". How to Balance the Equation "Na(s)"+"Cl"_2("g")"rarr"NaCl". Since there are two chlorine atoms on the left side, there needs to be two chlorine atoms on the right side. So I put a coefficient of two in front of the formula "NaCl". "Na(s)"+"Cl"_2("g")"rarr"2NaCl" Now there are two sodium and two chlorine atoms on the right side ...
Na + Cl2 --> 2 NaCl If 15 mol Na reacts with 15 mol Cl2 ... - Socratic
2018年2月25日 · You forgot to balance the equation for each mol of Cl_2, 2 mols of Na react, so therefore Na is limiting and Cl_2 is excess Check for LR 15 mol Cl_2 *(2mol Na)/ (1 mol Cl_2) Therefore 30 mol Na will be required to react, and since we don't have that amount, Na is limiting.
Cl_2 -> 2NaCl# is an example of which type of reaction? - Socratic
2017年1月28日 · The reaction you have here #2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))# is an example of a synthesis reaction.
What is the equation for sodium and chlorine react to form …
2017年3月14日 · 2Na + Cl_2 -> 2NaCl The skeletal equation: Na + Cl_2 -> NaCl Balanced: 2Na + Cl_2 -> 2NaCl
In the reaction 2Na + Cl2 --> 2NaCl Would 2Na be the ... - Socratic
2018年4月14日 · Just Na. We have the balanced equation: 2Na(s)+Cl_2(g)->2NaCl(s) Na(0) gets oxidized to Na(I), while Cl(0) gets reduced to Cl(-I). Since sodium got oxidized, it is the reducing agent in this equation. It doesn't matter if there was one sodium or three sodium atoms, the reducing agent is just the element or molecule itself, so Na will be the reducing agent here.
Sodium and chlorine react to form sodium chloride: 2Na (s) + Cl2 …
2017年6月15日 · Sodium and chlorine react to form sodium chloride: 2Na (s) + Cl2 (g) ----> 2NaCl (s) For the reaction of 44.0g Na with 69.9 g Cl2, what is the limiting reactant and what is the theoretical yield of sodium chloride in grams?
What is the balanced equation for sodium chloride? | Socratic
2014年1月13日 · This is a very vague question so I'll try to cover the basics sodium chloride is NaCl If you want a dissociate equation it'll be written as follows: NaCl(aq) -> Na+(aq) + Cl-(aq)
Sodium and chlorine gas react to produce sodium chloride. If
2017年5月20日 · "92.1 g" You know that 2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s)) and that the reaction produced "234 g" of sodium chloride. Convert this to moles by using the compound's molar mass 234 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44 color(red)(cancel(color(black)("g")))) = "4.004 moles NaCl" Now, you know that the sample of sodium metal reacted completely, which implies that ...
How many moles of chlorine gas (Cl2) would react with 5
2015年11月4日 · How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH
For the reaction 2NaI + Cl2 →2NaCl + I2 How many grams of
2018年3月12日 · 0.97528 \\ "g"~~1 \\ "g" We have the balanced equation (without state symbols), as 2NaI+Cl_2->2NaCl+I_2 What I first try to do is to find the limiting reactant with these types of problems, so let's do that first. NaI has a molar mass of 149.89 \\ "g/mol", so 2NaI has a molar mass of 149.89*2=299.78 \\ "g/mol". An average Cl atom has a molar mass of 35.453 \\ "g/mol", so the average molar mass ...