
How would you balance: Na + H2O --> NaOH + H2? - Socratic
2015年11月16日 · 2Na + 2H_2O -> 2NaOH +H_2 You have to count the number of atoms in both sides of the reaction to be equal, to make it a little easier you can make a list. So in the equation Na+H_2O->NaOH+H_2, there are 1-Na-1 2-H-3 1-O-1 So you multiply NaOH and H2O by 2, so you have 4 hydrogens in both sides, and then multiply Na by 2 to be equal to the NaOH you previously multiplied.
What is the oxidizing and reducing agent in Na + H2O --> NaOH …
2018年5月9日 · Hydrogen is formally reduced, and is thus the "oxidizing agent.." And so ....underbrace(H_2O(l) +e^(-) rarr 1/2H_2(g)uarr + HO^(-))_"reduction half equation" And natrium metal is oxidized....i.e. the metal is the "REDUCING agent..." underbrace(Na(s) rarr Na^+ + e^(-))_"oxidation half equation" And we simply add one t'other to remove the electrons.... Na(s) + H_2O(l) rarr 1/2H_2(g)uarr + NaOH ...
How would you balance: Na + H2O --> NaOH + H2? - Socratic
2015年11月27日 · How would you balance: Na + H2O --> NaOH + H2? Chemistry Chemical Reactions Balancing Chemical Equations ...
Balance the following chemical equation: Na + H3O → NaOH + H2
2023年5月30日 · Balance the following chemical equation: Na + H3O → NaOH + H2 Get the answers you need, now!
What type of reaction is this ----> NaH + H2O = NaOH + H2
2018年1月29日 · Is this not an acid-base reaction? underbrace(NaH(s))_"the base" + underbrace(H_2O(l))_"the acid" rarr NaOH(aq) + H_2(g)uarr
For the reaction 2Na + 2H_2O -> NaOH - Socratic
2017年5月25日 · For the reaction #2Na + 2H_2O -> NaOH + H_2#, how many grams of hydrogen are produced from 130 g of sodium? Chemistry Stoichiometry Equation Stoichiometry 1 Answer
What is the reducing agent in the reaction #2Na + 2H_2O - Socratic
2016年7月29日 · You're dealing with a redox reaction in which sodium metal, #"Na"#, is being oxidized to sodium cations, #"Na"^(+)#, and hydrogen is being reduced to hydrogen gas, #"H"_2#.
Na + H2O = NaOH+ H2 balance it - Brainly.in
2023年8月14日 · The chemical equation provided is the reaction of sodium (Na) with water (H2O) to produce sodium hydroxide (NaOH) and hydrogen gas (H2). To balance this equation, we need to make sure that the number of atoms of each element on the reactant side (left side) is equal to the number of atoms of the same element on the product side (right side).
A chemist reacted 0.05 moles of solid sodium with water to
2017年7月9日 · The stoichiometrically balanced equation for this is..... Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr Anyway you asked the mass of sodium reacted. This is simply 0.05*molxx22.99*g*mol^-1=1.15*g. Can you tell me (i) the volume of dihydrogen gas released given 298*K temperatures, and 1*atm pressures; and (ii) the pH of the resulting solution had it been diluted to 1*L? Enquiring minds want to ...
How do you balance Na + H_2O -> NaOH + H_2? | Socratic
2017年9月11日 · 2Na + 2H_2O -> 2NaOH + 2H_2 First, let's rewrite H_2O as HOH. It may seem weird, but when water reacts, it actually forms hydrogen and hydroxide ions. So, the "new" equation is: Na + HOH -> NaOH + H_2 Now we can see how many of each element/polyatomic ion we have on each side of the equation. Left: Na - 1 H - 1 OH - 1 Right: Na - 1 OH -1 H -2 Looking at what we have, there is an unequal amount ...