What is the difference in the uses of - Physics Stack Exchange
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definition - What does the $e^{i\omega t}$ notation mean in …
2020年12月6日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Why does the equation of a wave contain the term $\\omega t
2024年1月19日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
What is the difference between - Physics Stack Exchange
2020年9月29日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
quantum mechanics - Appearance of $e^{i(kx-\omega t)}$ in the ...
2022年1月23日 · One of the derivations of Schroedinger's Equation that I came across assumed the wave function for the particle to be $$\Psi = e^{i(kx-\omega t)} ,$$ and I hardly understand why.
Average of $\\sin^2 \\omega t$, $\\cos^2 \\omega t$ for long times
One way to think about this is in the frequency domain in terms of filtering.. The measuring apparatus has in effect a low-pass filter at the input with a corner frequency far below $\omega_0$.
Where must one use $x=A \\cos \\omega t$ and $x=A \\sin …
2021年3月6日 · From the specific wording of the question (I.e. it travels an additional 2'a' distance), I think you can start by imagining what simple harmonic motion looks like.
waves - How can $F_0\cos\omega t$ change to $F_0e^{i\omega …
This is a common trick used in linear differential equations with an inhomogeneous driving term. It's easier to algebraically manipulate complex exponentials than sines and cosines, and if you take the real part of the solution at the end, you end up at the same place anyway.
quantum mechanics - Why is $e^ {i (kx - \omega t)}$ a valid wave ...
2022年2月11日 · Why is $\psi = e^{i(kx - \omega t)}$ a valid wavefunction since it isn't finitely integrable on $\Bbb R$? I'm studying derivations of the Schrödinger Equation, which start with a simple wave functi...
Wave equation: $y=A \\sin(\\omega t-kx)$ or $y=A\\sin(kx …
2017年1月13日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.