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2007年12月4日 · [SOLVED] Q=mcT heat problem, were did i go wrong? Homework Statement If a 45g sample of aluminum at 22 degrees C is given 6.0 x 10^3 J of heat, what will its final temperature be? Homework Equations [tex]Q = mc \Delta T[/tex] The Attempt at a Solution i found in my textbook that aluminum has a specific heat capacity of 900 so c = 900.

2021年4月13日 · q = heat in joules or kilojoules, etc. m = mass usually in grams or kilograms. c = specific heat usually in J/g/degree

2014年2月20日 · Q = mC⌂T C = 1.007 ⌂T = -15 The Attempt at a Solution I don't know how to relate the m (usually a mass, right?) to a volume of air, as I assume that is the equations equivalent. I hope that makes sense...

FIND: a heat, Q The question asks for a heat in calories. FORMULAS: Q = m c ΔT and Q = m H f. The formula for temperature increase with heat application (Q = m c ΔT) will be used for the two legs A and C, the increase in temperature of the H 2 O as ice and as water. The formula for the energy used to melt the ice, Q = m H f, must also be used ...

2012年5月14日 · I understand for solids/liquids its always Q=mcΔT but for gases am I right to say ΔH=Q=ΔU+pΔV=m(c_p)ΔT for constant pressure and Q=ΔU=m(c_v)ΔT for constant volume? So if my textbook says "ΔU=n(3/2R)ΔT for any processes of monoatomic ideal gas" its wrong because for constant pressure processes you need to add work?

i think youre getting confused q = mct m = mass of liquid (so this would be in grams) t = change in temperature C is a specific constant to the liquid youre calculating energy for, e.g. for water itd be 4.2 J g^-1 K^-1, you just put the number into the formula in the exam.. infact you can do that for all 3 quantities, you only need to specifiy ...

2010年2月17日 · Q=mcT, variables with uncertainties are m and T. If it were only Q=mT, the %uncertainty of Q would be %uncertainty of m + % uncertainty of T. But c=constant (no uncertainties), so what is the uncertainty of Q when Q=mcT? Do you just multiply the constant to the %uncertainties of m and T...

2024年5月23日 · 1)to find q=mcT when given the volume and concentration of both solutions. why can't i divide the volume by 1000 to get dm3 and then divide the q by 1000 to get kJ mol. the answer involves keeping the volume as cm3 and dividing q by 1000 2) also what does 'assume that the density of solution is 1g cm-3'

2013年11月15日 · I know the formula q = mcT and that's the only formula I was taught before assigned these questions (in bold). 1. What mass of iron would be needed to have it increase by 6 degrees with 300J of heat. I am not sure what is meant by the increase of 6 degrees. How do you solve it without knowing the final or initial temperatures? 2.